anonymous
  • anonymous
a. Identify the function as being a linear, constant, quadratic, absolute-value, or step function. b. Find f(3). c. Find f(1/2) 1. f(x)=x 2. f(x)=2x^2 3. f(x)=[2-x]
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
The first one is constant. The second is quadradic and de second is is Absolute value.
anonymous
  • anonymous
Thank You, now what is part b) ????
anonymous
  • anonymous
Tfhe third is a absolute value function. The answers are for the first is a ordered pair (3,2); For the second just plug the valeu f(3)=2(3)^2. For the absolute value plug the value in the expression and you will find out.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
you made a mistake for the first question its f(x)=x so what is it?
anonymous
  • anonymous
and now whats part c) ????
anonymous
  • anonymous
Sorry the first one is a line.
anonymous
  • anonymous
Just plug the values in the equantions. For the first you have f(3)=3. So you will have the ordered pair (3,3).

Looking for something else?

Not the answer you are looking for? Search for more explanations.