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Kagome_gurl8

  • 3 years ago

Find a quadratic function to model the values in the table. Predict the value of y for x = 4. X|Y -1|-3 0|-2 3|-35

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  1. anonymous
    • 3 years ago
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    the constant must be \(-2\) so you have \[y=ax^2+bx-2\] as a start now we can set up a couple equations in \(a\) and \(b\)

  2. anonymous
    • 3 years ago
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    let \(x=-1\) you get \[a-b-2=-3\] or\[a-b=-1\]

  3. anonymous
    • 3 years ago
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    let \(x=3\) you get \[9a+3b-2=-35\] or \[9a+3b=-33\]

  4. anonymous
    • 3 years ago
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    solve the system \[a-b=-1\]\[9a+3b=-33\] to get your answer

  5. anonymous
    • 3 years ago
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    multiply first equation by 3, add it to the second get \[12a=-36\] so \(a=-3\) therefore \(b=-2\) and you get \[y=-3x^2-2b-2\]

  6. anonymous
    • 3 years ago
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    oops \[y=-3a^2-2x-2\]

  7. Kagome_gurl8
    • 3 years ago
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    so it would be y=-3a^2-2x-2;-58

  8. Kagome_gurl8
    • 3 years ago
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    @satellite73

  9. anonymous
    • 3 years ago
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    yes for the first one

  10. anonymous
    • 3 years ago
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    it would be \[y=-3x^2-2x-2\] with an \(x\) not an \(a\)

  11. Kagome_gurl8
    • 3 years ago
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    thanks so much. i've been working on this thing all weekend....

  12. Kagome_gurl8
    • 3 years ago
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    wait so 4 is going to be -56?

  13. Kagome_gurl8
    • 3 years ago
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    @satellite73

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