anonymous
  • anonymous
Algebra II question drawn below
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Algebra II question drawn below
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
|dw:1354499303778:dw|
anonymous
  • anonymous
First add the like terms in the denominator = 7 - square root of 5
anonymous
  • anonymous
\[3\div(7-\sqrt{5})\]

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anonymous
  • anonymous
\[3 (7+\sqrt{5})\] --------------- \[(7-\sqrt{5})(7+\sqrt{5})\]
anonymous
  • anonymous
the dashed line is the fraction bar
anonymous
  • anonymous
okay so it'd bbe 21+3sqrt"5" divided by 44. :) Was just stuck at one part and you helped me with it thx :)
anonymous
  • anonymous
good!! I was having trouble inserting th eequation!!!!!
anonymous
  • anonymous
Sorry!!!
anonymous
  • anonymous
Lol it's not a prob. :) Thx for taking your time to help :)
anonymous
  • anonymous
:)

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