Loujoelou
Last Algebra II question drawn below



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Loujoelou
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dw:1354499996745:dw

tejasree
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Add like terms that are in the bottom first

Loujoelou
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I know once you subtract below and do the top it becomes 3i/2i

Loujoelou
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and then multiply it by its conjugate +2+i right on both sides?

tejasree
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then multiply the top and the bottom with the conjugate of 2i, the conjugate is 2+i

Loujoelou
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oh okay that's where I was wrong

tejasree
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You just change the sign that is before the i/square root

Loujoelou
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k so once I do the bottom (2i)(2+i) it becomes +3 and the top becomes 36i, so it's 36i/3 right?

tejasree
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hmmm......i dont have a calc. or a pen wiht me right now! I guess you are correct! You may wnat to simplify it even more

tejasree
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3 goes into 36i = the final answer is 1  2i

Loujoelou
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thx :) I mean I would simplify more but the answer is not simplified on my choices so yep thx a ton for helping! :)

tejasree
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no problem!!! :)

Loujoelou
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oh hey could you help me with one more problem I need to doublecheck?

tejasree
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sure I will if I can!! :)

Loujoelou
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dw:1354500581181:dw

tejasree
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\[(x ^{4/5})^{3/7}\]

tejasree
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I am guessing you multiply both exponents! (4/5)(3/7)

Loujoelou
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k that's what I did , just wanted to make sure thx :)

tejasree
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Good Job! :)

Minneemse
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can you help me? please!

Minneemse
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tejasree?

tejasree
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I am looking at your question! :)

Minneemse
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thank you thank you thank you!!!!