## Loujoelou 2 years ago Last Algebra II question drawn below

1. Loujoelou

|dw:1354499996745:dw|

2. tejasree

Add like terms that are in the bottom first

3. Loujoelou

I know once you subtract below and do the top it becomes 3i/-2-i

4. Loujoelou

and then multiply it by its conjugate +2+i right on both sides?

5. tejasree

then multiply the top and the bottom with the conjugate of -2-i, the conjugate is -2+i

6. Loujoelou

oh okay that's where I was wrong

7. tejasree

You just change the sign that is before the i/square root

8. Loujoelou

k so once I do the bottom (-2-i)(-2+i) it becomes +3 and the top becomes -3-6i, so it's -3-6i/3 right?

9. tejasree

hmmm......i dont have a calc. or a pen wiht me right now! I guess you are correct! You may wnat to simplify it even more

10. tejasree

3 goes into -3-6i = the final answer is -1 - 2i

11. Loujoelou

thx :) I mean I would simplify more but the answer is not simplified on my choices so yep thx a ton for helping! :)

12. tejasree

no problem!!! :)

13. Loujoelou

oh hey could you help me with one more problem I need to double-check?

14. tejasree

sure I will if I can!! :)

15. Loujoelou

|dw:1354500581181:dw|

16. tejasree

\[(x ^{4/5})^{3/7}\]

17. tejasree

I am guessing you multiply both exponents! (4/5)(3/7)

18. Loujoelou

k that's what I did , just wanted to make sure thx :)

19. tejasree

Good Job! :)

20. Minneemse

21. Minneemse

tejasree?

22. tejasree

I am looking at your question! :)

23. Minneemse

thank you thank you thank you!!!!