anonymous
  • anonymous
Last Algebra II question drawn below
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1354499996745:dw|
anonymous
  • anonymous
Add like terms that are in the bottom first
anonymous
  • anonymous
I know once you subtract below and do the top it becomes 3i/-2-i

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anonymous
  • anonymous
and then multiply it by its conjugate +2+i right on both sides?
anonymous
  • anonymous
then multiply the top and the bottom with the conjugate of -2-i, the conjugate is -2+i
anonymous
  • anonymous
oh okay that's where I was wrong
anonymous
  • anonymous
You just change the sign that is before the i/square root
anonymous
  • anonymous
k so once I do the bottom (-2-i)(-2+i) it becomes +3 and the top becomes -3-6i, so it's -3-6i/3 right?
anonymous
  • anonymous
hmmm......i dont have a calc. or a pen wiht me right now! I guess you are correct! You may wnat to simplify it even more
anonymous
  • anonymous
3 goes into -3-6i = the final answer is -1 - 2i
anonymous
  • anonymous
thx :) I mean I would simplify more but the answer is not simplified on my choices so yep thx a ton for helping! :)
anonymous
  • anonymous
no problem!!! :)
anonymous
  • anonymous
oh hey could you help me with one more problem I need to double-check?
anonymous
  • anonymous
sure I will if I can!! :)
anonymous
  • anonymous
|dw:1354500581181:dw|
anonymous
  • anonymous
\[(x ^{4/5})^{3/7}\]
anonymous
  • anonymous
I am guessing you multiply both exponents! (4/5)(3/7)
anonymous
  • anonymous
k that's what I did , just wanted to make sure thx :)
anonymous
  • anonymous
Good Job! :)
anonymous
  • anonymous
can you help me? please!
anonymous
  • anonymous
tejasree?
anonymous
  • anonymous
I am looking at your question! :)
anonymous
  • anonymous
thank you thank you thank you!!!!

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