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joycemullins

  • 3 years ago

and another one......plz help

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  1. joycemullins
    • 3 years ago
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    \[\frac{ 2a+3 }{ 4a-5 }-\frac{ a-2 }{ 4a-5}\]

  2. tkhunny
    • 3 years ago
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    How would you do this? \(\dfrac{7}{3} - \dfrac{13}{5}\)?

  3. viniterranova
    • 3 years ago
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    Let me sse

  4. joycemullins
    • 3 years ago
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    i would cross multiply

  5. tkhunny
    • 3 years ago
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    Well, I hope you mean that you would find a commn denominator and then add. Very good. Can you do that with the original problem statement?

  6. lrbrock
    • 3 years ago
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    same denominators... simply subtract numerators

  7. joycemullins
    • 3 years ago
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    ummmm.....idk

  8. joycemullins
    • 3 years ago
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    4a-5

  9. tejasree
    • 3 years ago
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    (2a+3)-(a-2) ======== 4a-5

  10. tejasree
    • 3 years ago
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    2a -a + 3 +2 = a+5 ---->numerator

  11. tejasree
    • 3 years ago
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    a+5 === --------> the answer 4a-5

  12. joycemullins
    • 3 years ago
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    ok i get it

  13. tejasree
    • 3 years ago
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    :)

  14. viniterranova
    • 3 years ago
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    Great.

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