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unkabogable

help me to integrate

  • one year ago
  • one year ago

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  1. unkabogable
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    |dw:1354504731249:dw|

    • one year ago
  2. viniterranova
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    We will see.

    • one year ago
  3. Minneemse
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    please someone help me with my problem!!!

    • one year ago
  4. satellite73
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    i would start with \[\frac{x+2}{x^2+2x+5}+\frac{1}{x^2+2x+5}\] because the first one gives way to a simple \(u\) sub the second one is a pain though

    • one year ago
  5. lrbrock
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    \[\int\limits_{a}^{b} (x+3) * (x^2 + 2x +5)^-1 dx\]

    • one year ago
  6. hieuvo
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    |dw:1354504176605:dw|

    • one year ago
  7. satellite73
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    i guess not that much of a pain complete the square, solution above

    • one year ago
  8. unkabogable
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    |dw:1354505437528:dw| u = x+1 ; a= 2 ?

    • one year ago
  9. hieuvo
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    the first one, let u be the denominator, then du will be x+2dx, so this is regular integrate(1/u)du

    • one year ago
  10. hieuvo
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    i would make the first numerator x+1, the second numerator is 2

    • one year ago
  11. unkabogable
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    okay ..

    • one year ago
  12. unkabogable
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    from the top pls.?

    • one year ago
  13. unkabogable
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    |dw:1354505864451:dw| ?

    • one year ago
  14. hieuvo
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    |dw:1354504775593:dw|

    • one year ago
  15. hieuvo
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    and the other one just like above but multiplied by 2 :D

    • one year ago
  16. unkabogable
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    for the second one? |dw:1354506253527:dw| kinda impossibele @hieuvo

    • one year ago
  17. hieuvo
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    |dw:1354505287482:dw|

    • one year ago
  18. unkabogable
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    its unclear to me :(

    • one year ago
  19. hieuvo
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    |dw:1354505588414:dw|

    • one year ago
  20. hieuvo
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    is that what you're confused ?

    • one year ago
  21. unkabogable
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    okay i get it now thanks! :)

    • one year ago
  22. hieuvo
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    you're welcome

    • one year ago
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