LAST TWO QUESTIONS. PLEASE HELP

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LAST TWO QUESTIONS. PLEASE HELP

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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@saifoo.khan
Let's solve the cow one first.

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Other answers:

Total area = 36000 Hence: 400G + 1200C = 36,000
If the farmer raises only cows, then: (Total area)/(Area needed for cows) = 36000/1200
Try the same thing for last part.
36000/400
How do I graph it though?
400G + 1200C = 36,000 Take Goats on y-axis.
Just like" Ay + Bx = C
Can you show me?
400G + 1200C = 36,000 Ay + Bx = C You have to make G the subject. 400G = 1200C - 36000 G = (1200C-36000)/400
Thanks :D, so the y-int is 0,-90 and the x-int is 30,0?
Did i typo!
400G + 1200C = 36,000 Ay + Bx = C You have to make G the subject. 400G = -1200C + 36000 G = (-1200C + 36000)/400

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