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LAST TWO QUESTIONS. PLEASE HELP

Mathematics
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@saifoo.khan
Let's solve the cow one first.

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Other answers:

Total area = 36000 Hence: 400G + 1200C = 36,000
If the farmer raises only cows, then: (Total area)/(Area needed for cows) = 36000/1200
Try the same thing for last part.
36000/400
How do I graph it though?
400G + 1200C = 36,000 Take Goats on y-axis.
Just like" Ay + Bx = C
Can you show me?
400G + 1200C = 36,000 Ay + Bx = C You have to make G the subject. 400G = 1200C - 36000 G = (1200C-36000)/400
Thanks :D, so the y-int is 0,-90 and the x-int is 30,0?
Did i typo!
400G + 1200C = 36,000 Ay + Bx = C You have to make G the subject. 400G = -1200C + 36000 G = (-1200C + 36000)/400

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