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AdhaZeera

LAST TWO QUESTIONS. PLEASE HELP

  • one year ago
  • one year ago

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  1. AdhaZeera
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    • one year ago
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  2. AdhaZeera
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    @saifoo.khan

    • one year ago
  3. saifoo.khan
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    Let's solve the cow one first.

    • one year ago
  4. saifoo.khan
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    Total area = 36000 Hence: 400G + 1200C = 36,000

    • one year ago
  5. saifoo.khan
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    If the farmer raises only cows, then: (Total area)/(Area needed for cows) = 36000/1200

    • one year ago
  6. saifoo.khan
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    Try the same thing for last part.

    • one year ago
  7. AdhaZeera
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    36000/400

    • one year ago
  8. AdhaZeera
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    How do I graph it though?

    • one year ago
  9. saifoo.khan
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    400G + 1200C = 36,000 Take Goats on y-axis.

    • one year ago
  10. saifoo.khan
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    Just like" Ay + Bx = C

    • one year ago
  11. AdhaZeera
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    Can you show me?

    • one year ago
  12. saifoo.khan
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    400G + 1200C = 36,000 Ay + Bx = C You have to make G the subject. 400G = 1200C - 36000 G = (1200C-36000)/400

    • one year ago
  13. AdhaZeera
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    Thanks :D, so the y-int is 0,-90 and the x-int is 30,0?

    • one year ago
  14. saifoo.khan
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    Did i typo!

    • one year ago
  15. saifoo.khan
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    400G + 1200C = 36,000 Ay + Bx = C You have to make G the subject. 400G = -1200C + 36000 G = (-1200C + 36000)/400

    • one year ago
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