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AdhaZeera

  • 2 years ago

LAST TWO QUESTIONS. PLEASE HELP

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  1. AdhaZeera
    • 2 years ago
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  2. AdhaZeera
    • 2 years ago
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    @saifoo.khan

  3. saifoo.khan
    • 2 years ago
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    Let's solve the cow one first.

  4. saifoo.khan
    • 2 years ago
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    Total area = 36000 Hence: 400G + 1200C = 36,000

  5. saifoo.khan
    • 2 years ago
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    If the farmer raises only cows, then: (Total area)/(Area needed for cows) = 36000/1200

  6. saifoo.khan
    • 2 years ago
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    Try the same thing for last part.

  7. AdhaZeera
    • 2 years ago
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    36000/400

  8. AdhaZeera
    • 2 years ago
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    How do I graph it though?

  9. saifoo.khan
    • 2 years ago
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    400G + 1200C = 36,000 Take Goats on y-axis.

  10. saifoo.khan
    • 2 years ago
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    Just like" Ay + Bx = C

  11. AdhaZeera
    • 2 years ago
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    Can you show me?

  12. saifoo.khan
    • 2 years ago
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    400G + 1200C = 36,000 Ay + Bx = C You have to make G the subject. 400G = 1200C - 36000 G = (1200C-36000)/400

  13. AdhaZeera
    • 2 years ago
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    Thanks :D, so the y-int is 0,-90 and the x-int is 30,0?

  14. saifoo.khan
    • 2 years ago
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    Did i typo!

  15. saifoo.khan
    • 2 years ago
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    400G + 1200C = 36,000 Ay + Bx = C You have to make G the subject. 400G = -1200C + 36000 G = (-1200C + 36000)/400

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