A farmer has 336 ft of fencing and wants to build two identical pens for his prize-winning pigs. The pens will be arranged as shown. Determine the dimensions of a pen that will maximize its area.

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A farmer has 336 ft of fencing and wants to build two identical pens for his prize-winning pigs. The pens will be arranged as shown. Determine the dimensions of a pen that will maximize its area.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Fencing = 3x + 4y 336 = 3x + 4y Area = 2xy A = 2xy x = (336-4y) / 3 A = 2[(336-4y)/3] y Find dA/dy and equate to 0. solve for y.
I dont understand this part: x = (336-4y) / 3 A = 2[(336-4y)/3] y Find dA/dy and equate to 0. solve for y.

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i rearranged the fencing equation in terms of x and subbed it into the area equation. find the derivative of A with respect to y. make it equal 0. solve for y. sub y into original equation and solve for x.
I dont know deriatives yet!
pls help me! I have to study for my final exam!!!
instead of taking the derivative, find the vertex of the quadratic equation.
ok! I will try and call for you when I dont get it!
the x value of your vertex will be y

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