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MAJOR HELP PLEASE!! Verify that the equation is an identity. Show all your work. (sin x + cos x)^2 - 1 = sin 2x

Mathematics
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(a+b)^2 =a^2+2ab+b^2 so (sin x + cos x)^2 - 1 sin^2x+2sinxcosx+cos^2x -1 2sinxcosx +sin^2x+cos^2x -1 i think u can do from here.
use formula \[(a+b)^{2} = a^{2} + 2ab + b^{2}\], expand that out and you will see what you need to
@nubeer i'm sorry i am a little lost, could you please explain further?

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Other answers:

2sinxcosx +sin^2x+cos^2x -1 have you understood how i have got this part?
yes with the formula right?
2sinxcosx +sin^2x+cos^2x -1 what is sin^2x+cos^2x = ?
1?
yes.. now put this 1 in the equation 2sinxcosx +sin^2x+cos^2x -1 2sinxcosx +1-1.. got it?
2sinxcosx
@nubeer right?
yes and 2sinxcosx=sin2x (according to the identity)
you're awesome..thanks!!!

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