A community for students.
Here's the question you clicked on:
 0 viewing
coolaidd
 3 years ago
(1) Write log9+1/3log729 as a single logarithm.
(2) Write log[2]51/2log[2]169 as a single logarithm.
coolaidd
 3 years ago
(1) Write log9+1/3log729 as a single logarithm. (2) Write log[2]51/2log[2]169 as a single logarithm.

This Question is Closed

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.01) the 1/3 would just be the exponent of log(729) so log(729)^1/3 and then we use log rule log(ab)= log(a)+log(b) to get log(9)(729)^(1/3)

coolaidd
 3 years ago
Best ResponseYou've already chosen the best response.0so i solve that? @jbovey i got In9/in10

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0no thats the answer for #1. Since it says just write as single log you wouldn't have to solve any further

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0it just wants you to use the log rules and combine

coolaidd
 3 years ago
Best ResponseYou've already chosen the best response.0oooh ok.. so what about #2?

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0Im kind of confused by the way you wrote it. Can u draw the equation out so I can see?

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0I know you'll have to use log rule 3 which is log(a)log(b)= log(a)/(b)

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0so are 5 and 169 the exponents?

coolaidd
 3 years ago
Best ResponseYou've already chosen the best response.0no those are regular sized..

geoffb
 3 years ago
Best ResponseYou've already chosen the best response.1The 2s are bases. She means \(\log_{2} 5  \frac{1}{2} \log_{2} 169\)

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0ohhhh sorry about that, thanks @geoffb

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0wait so wouldnt that make 5 and 169 the exponents? @geoffb

geoffb
 3 years ago
Best ResponseYou've already chosen the best response.1You would just need to maintain base 2. It's nice because both logs use base 2.

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.1just a quick point on your first question... \[\frac{1}{3}\log(729) = \log(\sqrt[3]{729}) = \log(9)\] so then \[\log(9) + \frac{1}{3}\log(729) = \log(9) + \log(9) = \log(9 \times 9) = \log(81).. or... 2\log(9)\] just a suggestion... when compared to \[\log(\sqrt[3]{6561})\] not quite the same things...

geoffb
 3 years ago
Best ResponseYou've already chosen the best response.1So, like you said, you could start by moving the 1/2 up as an exponent. $$\large \log_{2} 5  \frac{1}{2} \log_{2} 169 = \log_{2} 5  \log_{2} 169^{\frac{1}{2}} = \log_{2} (\frac{5}{13})$$

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks bro @campbell_st I was close lol

coolaidd
 3 years ago
Best ResponseYou've already chosen the best response.0ok..so would that be the final answer @geoffb ?

jbovey
 3 years ago
Best ResponseYou've already chosen the best response.0yeah thats the answer @coolaidd
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.