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Find the point on the graph of √(x+1) that lies closest to point ( 4,0).

  • one year ago
  • one year ago

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  1. SomeBloke
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    What problem are you having with that?

    • one year ago
  2. EulerGroupie
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    Overall concept: Substitute points into the distance formula find a minimum using derivatives. \[d=\sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}}\]where\[(x _{1}, y _{1})=(4,0)\]\[(x _{2},y _{2})=(x, \sqrt{x+1})\]Simplify. Take the derivative. Find critical points by setting the derivative to zero. Determine if there is a relative minimum and what it is. Plug that back into the original function to find the y value of the point.

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