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Find the point on the graph of √(x+1) that lies closest to point ( 4,0).
 one year ago
 one year ago
Find the point on the graph of √(x+1) that lies closest to point ( 4,0).
 one year ago
 one year ago

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galanhBest ResponseYou've already chosen the best response.1
The distance between a point on the curve and the point (0,4) is: \[d= \sqrt{(x4)**2+x+1}=\sqrt{x**2 7x+17}\] \[d=\sqrt{(x3.5)**2 +4.75}\] d is minimum when x=3.5 and y=sqrt(3.5+1)=sqrt(4.5)=2.12
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
Is that the formula for the distance of a curve to a point, the one they teach in grade 10 or something?
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
we dont want the distance, we want the point closest, and the answer is wrong :/
 one year ago

galanhBest ResponseYou've already chosen the best response.1
the closed point is (3.5,2.12)
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
wait... is that a basic equation? it's for my calculus class and I didn't see you use any derivative or anything
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
@galanh its odd my solution sheet has a different way, I'm just trying to understand the method sorry :/
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
thats the solution using derivative, but I don't understand why we would set the first derivative to 0 to find the critical points, just seems odd to me
 one year ago

galanhBest ResponseYou've already chosen the best response.1
Thanks for the solution with derivative.
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
do you understand that solution? I don't understand it that was why i asked the question in the first place
 one year ago

galanhBest ResponseYou've already chosen the best response.1
I am not good with derivatives! derivative of a function equal to zero, gives you the minimum of the function!
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
Errr thanks for the help :) i'll try to figure out the rest on my own haha
 one year ago
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