anonymous
  • anonymous
Find the point on the graph of √(x+1) that lies closest to point ( 4,0).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
The distance between a point on the curve and the point (0,4) is: \[d= \sqrt{(x-4)**2+x+1}=\sqrt{x**2 -7x+17}\] \[d=\sqrt{(x-3.5)**2 +4.75}\] d is minimum when x=3.5 and y=sqrt(3.5+1)=sqrt(4.5)=2.12
anonymous
  • anonymous
Is that the formula for the distance of a curve to a point, the one they teach in grade 10 or something?
anonymous
  • anonymous
we dont want the distance, we want the point closest, and the answer is wrong :/

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anonymous
  • anonymous
the closed point is (3.5,2.12)
anonymous
  • anonymous
wait... is that a basic equation? it's for my calculus class and I didn't see you use any derivative or anything
anonymous
  • anonymous
@galanh its odd my solution sheet has a different way, I'm just trying to understand the method sorry :/
anonymous
  • anonymous
I used this graph
anonymous
  • anonymous
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anonymous
  • anonymous
thats the solution using derivative, but I don't understand why we would set the first derivative to 0 to find the critical points, just seems odd to me
anonymous
  • anonymous
Thanks for the solution with derivative.
anonymous
  • anonymous
do you understand that solution? I don't understand it that was why i asked the question in the first place
anonymous
  • anonymous
I am not good with derivatives! derivative of a function equal to zero, gives you the minimum of the function!
anonymous
  • anonymous
Errr thanks for the help :) i'll try to figure out the rest on my own haha
anonymous
  • anonymous
My pleasure!

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