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swin2013

  • 3 years ago

Use the derivative of the function y - f(x) to find the points at which f has a a) local max b) local min c) point of inflection

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  1. swin2013
    • 3 years ago
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    y'= (x-1)^2 (x-2)

  2. petewe
    • 3 years ago
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    equate the derivative to 0 to find any max or min equate the second derivative to 0 to find any poi

  3. swin2013
    • 3 years ago
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    ohhh ok thanks!@

  4. swin2013
    • 3 years ago
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    so it's (x-1)^2 (x-2) = 0 x = 2, 0 and does (x-1)^2 has an x value?

  5. petewe
    • 3 years ago
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    of course it does

  6. swin2013
    • 3 years ago
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    oh so it's -1 and 1 also?

  7. petewe
    • 3 years ago
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    (x-1)^2 = 0 solve for x

  8. swin2013
    • 3 years ago
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    (x-1)(x-1)(x-2) = 0 correct? to find max and mins?

  9. swin2013
    • 3 years ago
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    since (x-1)^2 is the same as (x-1) (x-1)

  10. petewe
    • 3 years ago
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    ^ no (x^2 -1) = (x-1)(x+1)

  11. swin2013
    • 3 years ago
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    how is it x^2 - 1? if the squared is outside the parenthesis?? it's not (x^2-1) because it says (x-1)^2? isn't that different? :0

  12. petewe
    • 3 years ago
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    what i'm saying is (x-1)^2 =/= (x-1)(x+1)

  13. swin2013
    • 3 years ago
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    does not equal?

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