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swin2013
Group Title
Use the derivative of the function y  f(x) to find the points at which f has a
a) local max
b) local min
c) point of inflection
 2 years ago
 2 years ago
swin2013 Group Title
Use the derivative of the function y  f(x) to find the points at which f has a a) local max b) local min c) point of inflection
 2 years ago
 2 years ago

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swin2013 Group TitleBest ResponseYou've already chosen the best response.0
y'= (x1)^2 (x2)
 2 years ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
equate the derivative to 0 to find any max or min equate the second derivative to 0 to find any poi
 2 years ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
ohhh ok thanks!@
 2 years ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
so it's (x1)^2 (x2) = 0 x = 2, 0 and does (x1)^2 has an x value?
 2 years ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
of course it does
 2 years ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
oh so it's 1 and 1 also?
 2 years ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
(x1)^2 = 0 solve for x
 2 years ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
(x1)(x1)(x2) = 0 correct? to find max and mins?
 2 years ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
since (x1)^2 is the same as (x1) (x1)
 2 years ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
^ no (x^2 1) = (x1)(x+1)
 2 years ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
how is it x^2  1? if the squared is outside the parenthesis?? it's not (x^21) because it says (x1)^2? isn't that different? :0
 2 years ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
what i'm saying is (x1)^2 =/= (x1)(x+1)
 2 years ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
does not equal?
 2 years ago
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