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swin2013
Group Title
Use the derivative of the function y  f(x) to find the points at which f has a
a) local max
b) local min
c) point of inflection
 one year ago
 one year ago
swin2013 Group Title
Use the derivative of the function y  f(x) to find the points at which f has a a) local max b) local min c) point of inflection
 one year ago
 one year ago

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swin2013 Group TitleBest ResponseYou've already chosen the best response.0
y'= (x1)^2 (x2)
 one year ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
equate the derivative to 0 to find any max or min equate the second derivative to 0 to find any poi
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
ohhh ok thanks!@
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
so it's (x1)^2 (x2) = 0 x = 2, 0 and does (x1)^2 has an x value?
 one year ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
of course it does
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
oh so it's 1 and 1 also?
 one year ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
(x1)^2 = 0 solve for x
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
(x1)(x1)(x2) = 0 correct? to find max and mins?
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
since (x1)^2 is the same as (x1) (x1)
 one year ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
^ no (x^2 1) = (x1)(x+1)
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
how is it x^2  1? if the squared is outside the parenthesis?? it's not (x^21) because it says (x1)^2? isn't that different? :0
 one year ago

petewe Group TitleBest ResponseYou've already chosen the best response.0
what i'm saying is (x1)^2 =/= (x1)(x+1)
 one year ago

swin2013 Group TitleBest ResponseYou've already chosen the best response.0
does not equal?
 one year ago
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