Use the derivative of the function y - f(x) to find the points at which f has a a) local max b) local min c) point of inflection

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Use the derivative of the function y - f(x) to find the points at which f has a a) local max b) local min c) point of inflection

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

y'= (x-1)^2 (x-2)
equate the derivative to 0 to find any max or min equate the second derivative to 0 to find any poi
ohhh ok thanks!@

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

so it's (x-1)^2 (x-2) = 0 x = 2, 0 and does (x-1)^2 has an x value?
of course it does
oh so it's -1 and 1 also?
(x-1)^2 = 0 solve for x
(x-1)(x-1)(x-2) = 0 correct? to find max and mins?
since (x-1)^2 is the same as (x-1) (x-1)
^ no (x^2 -1) = (x-1)(x+1)
how is it x^2 - 1? if the squared is outside the parenthesis?? it's not (x^2-1) because it says (x-1)^2? isn't that different? :0
what i'm saying is (x-1)^2 =/= (x-1)(x+1)
does not equal?

Not the answer you are looking for?

Search for more explanations.

Ask your own question