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swin2013 Group Title

Use the derivative of the function y - f(x) to find the points at which f has a a) local max b) local min c) point of inflection

  • one year ago
  • one year ago

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  1. swin2013 Group Title
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    y'= (x-1)^2 (x-2)

    • one year ago
  2. petewe Group Title
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    equate the derivative to 0 to find any max or min equate the second derivative to 0 to find any poi

    • one year ago
  3. swin2013 Group Title
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    ohhh ok thanks!@

    • one year ago
  4. swin2013 Group Title
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    so it's (x-1)^2 (x-2) = 0 x = 2, 0 and does (x-1)^2 has an x value?

    • one year ago
  5. petewe Group Title
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    of course it does

    • one year ago
  6. swin2013 Group Title
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    oh so it's -1 and 1 also?

    • one year ago
  7. petewe Group Title
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    (x-1)^2 = 0 solve for x

    • one year ago
  8. swin2013 Group Title
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    (x-1)(x-1)(x-2) = 0 correct? to find max and mins?

    • one year ago
  9. swin2013 Group Title
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    since (x-1)^2 is the same as (x-1) (x-1)

    • one year ago
  10. petewe Group Title
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    ^ no (x^2 -1) = (x-1)(x+1)

    • one year ago
  11. swin2013 Group Title
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    how is it x^2 - 1? if the squared is outside the parenthesis?? it's not (x^2-1) because it says (x-1)^2? isn't that different? :0

    • one year ago
  12. petewe Group Title
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    what i'm saying is (x-1)^2 =/= (x-1)(x+1)

    • one year ago
  13. swin2013 Group Title
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    does not equal?

    • one year ago
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