Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

coolaidd

  • 3 years ago

..

  • This Question is Closed
  1. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you know your basic logarithmic rules?

  2. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Alright well for the first one I would do Ln(1/2) ^x = ln15 then you can bring the exponent in front therefore giving you xln(1/2) = ln 15. Then you get x= ln (15) / ln(1/2)

  3. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    for the second you have the rule of Log(a)b= c is the same as a^c = b

  4. coolaidd
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok..so how do i solve 2?

  5. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you have a ruole saying a√x = √b . Both a and b are constant. Therefore in this case you would have x =729 ending up as ( because what you do on the left you ahve to do on the right) 3 √x^3 =3√729 You should have a button on your calculator labelled as x√

  6. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    err sorry I meant the rule is a√x^a = a√b

  7. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    where the a's in : a√x^a cancel out. ( same as a square root and a square)

  8. coolaidd
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok..

  9. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you understand or I made it too complicated?

  10. coolaidd
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    kind of complicated..

  11. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    alright I'll try to water it down. You know sqrt(x) = (x)^1/2 right? You have probably learned in algebra sqrt(x^2) ends up as X only because the sqrt cancels out with the square (^2) THEREFORE if you have x^3 = 729, you don't have an answer you WANT X= ? Therefore, you have to CANCEL OUT the ^3 somehow. The only way, like how you cancel a ^2 is by SQUARE ROOTING THE EXPRESSION so you end up with 3(sqrt)(x^3) = (x^3)^(1/3). By the rule of exponent, you multiplied the 2 of the ( 3*1/3) = 3/3 = 1 GIVING YOU X WHAT YOU DO ON THE LEFT YOU DO TO THE RIGHT THEREFORE (729)^(1/3) OR 3(sqrt)(729) the answer should be 9

  12. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I'm sorry if I made this too complicated, I just tried to explain the concept to it

  13. coolaidd
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    perfectly fine..thank you Marc!

  14. MarcLeclair
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    np

  15. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy