Here's the question you clicked on:
kenneyfamily
distance between lines? 6x - 8y = 3 6x - 8y = -5
Hint: Use the distance formula for lines
\[\large d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]
There's two ways to do it. You can either use the distance formula for LINES (yes there is such a thing) or you can find the line perpendicular to both given lines since they are parallel.
It's just a formula bro. It's nothing to get overly eager and excited about.
ok the question is the distance is 4/5. true or false?
The formula is \[ d = \frac{|ax + by + c|}{\sqrt{a^2 + b^2}}\] Where (x,y) is a point on one of the lines and a, b, c are the coefficients of the other line.
And I should say that this is specifically the formula for the distance between two PARALLEL lines.
(x,y) = (.5,0) is a point on the first given line. So use a = 6, b = -8, c = 5 for the other one.
how would you non parallel lines? @Hero such as x + y - 1 = 0 and y = -x + 6
If the lines are not parallel, then the distance between them would not be consistent.
That formula I gave you (as I stated previously) is for PARALLEL lines only
hmm but it is answerable
Well, actually, what you just posted are two parallel lines.