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kenneyfamily

  • 3 years ago

distance between lines? 6x - 8y = 3 6x - 8y = -5

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  1. Hero
    • 3 years ago
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    Hint: Use the distance formula for lines

  2. ChmE
    • 3 years ago
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    \[\large d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]

  3. ChmE
    • 3 years ago
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    That is for points

  4. Hero
    • 3 years ago
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    There's two ways to do it. You can either use the distance formula for LINES (yes there is such a thing) or you can find the line perpendicular to both given lines since they are parallel.

  5. Hero
    • 3 years ago
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    It's just a formula bro. It's nothing to get overly eager and excited about.

  6. kenneyfamily
    • 3 years ago
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    ok the question is the distance is 4/5. true or false?

  7. Hero
    • 3 years ago
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    The formula is \[ d = \frac{|ax + by + c|}{\sqrt{a^2 + b^2}}\] Where (x,y) is a point on one of the lines and a, b, c are the coefficients of the other line.

  8. Hero
    • 3 years ago
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    And I should say that this is specifically the formula for the distance between two PARALLEL lines.

  9. RadEn
    • 3 years ago
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    8/10 = 4/5 correct

  10. Hero
    • 3 years ago
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    (x,y) = (.5,0) is a point on the first given line. So use a = 6, b = -8, c = 5 for the other one.

  11. Hero
    • 3 years ago
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    Are you happy @ChmE ?

  12. kenneyfamily
    • 3 years ago
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    how would you non parallel lines? @Hero such as x + y - 1 = 0 and y = -x + 6

  13. Hero
    • 3 years ago
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    If the lines are not parallel, then the distance between them would not be consistent.

  14. Hero
    • 3 years ago
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    That formula I gave you (as I stated previously) is for PARALLEL lines only

  15. kenneyfamily
    • 3 years ago
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    hmm but it is answerable

  16. Hero
    • 3 years ago
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    Well, actually, what you just posted are two parallel lines.

  17. Hero
    • 3 years ago
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    y = -x + 1 and y = -x + 6

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