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 2 years ago
Please help!
Solve the system of equations using matrices. Use Gaussian elimination with backsubstitution.
3x + 5y  2w = 13
2x + 7z  w = 1
4y + 3z + 3w = 1
x + 2y + 4z = 5
 2 years ago
Please help! Solve the system of equations using matrices. Use Gaussian elimination with backsubstitution. 3x + 5y  2w = 13 2x + 7z  w = 1 4y + 3z + 3w = 1 x + 2y + 4z = 5

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mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1[ 3 5 0 2 13 ] [ 2 0 7 1 1 ] [ 0 4 3 3 1 ] [ 1 2 4 0 5 ] can you continue next ?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1gaussian is to make it like dw:1354591428681:dw

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1@alyssababy7 can you follow and do the next steps? .:D let me know.... :D

alyssababy7
 2 years ago
Best ResponseYou've already chosen the best response.0A. {(1, (20/3), 0, 2/5)} B. {(1, 2, 0, 3)} C. {(3/4, 2, 0, 3/4)} D. {(4/3, (13/20) , 0, 5/2)} My options

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1did you try solving that yet? after back substitution what did you get for x,y,z and w?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1i did this this way, from [ 3 5 0 2 13 ] [ 2 0 7 1 1 ] [ 0 4 3 3 1 ] [ 1 2 4 0 5 ] [ 1 2 4 0 5 ] mult by 1> [ 1 2 4 0 5 ] [ 0 4 3 3 1 ] [ 0 4 3 3 1 ] [ 2 0 7 1 1 ] [ 2 0 7 1 1 ] [ 3 5 0 2 13 ] [ 3 5 0 2 13 ] now its easy to manipulate them to be echelon form

alyssababy7
 2 years ago
Best ResponseYou've already chosen the best response.0I just don't understand this.

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.1[ 1 2 4 0 5 ] [ 0 4 3 3 1 ] [ 2 0 7 1 1 ] [ 3 5 0 2 13 ] try to continue this one tobe gaussian echelon form
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