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alyssababy7
Please help! Solve the system of equations using matrices. Use Gaussian elimination with back-substitution. 3x + 5y - 2w = -13 2x + 7z - w = -1 4y + 3z + 3w = 1 -x + 2y + 4z = -5
[ 3 5 0 -2 -13 ] [ 2 0 7 -1 -1 ] [ 0 4 3 3 1 ] [ -1 2 4 0 -5 ] can you continue next ?
gaussian is to make it like |dw:1354591428681:dw|
@alyssababy7 can you follow and do the next steps? .:D let me know.... :D
A. {(-1, -(20/3), 0, 2/5)} B. {(1, -2, 0, 3)} C. {(3/4, -2, 0, 3/4)} D. {(4/3, -(13/20) , 0, 5/2)} My options
did you try solving that yet? after back substitution what did you get for x,y,z and w?
i did this this way, from [ 3 5 0 -2 -13 ] [ 2 0 7 -1 -1 ] [ 0 4 3 3 1 ] [ -1 2 4 0 -5 ] [ -1 2 4 0 -5 ] mult by -1--> [ 1 -2 -4 0 5 ] [ 0 4 3 3 1 ] [ 0 4 3 3 1 ] [ 2 0 7 -1 -1 ] [ 2 0 7 -1 -1 ] [ 3 5 0 -2 -13 ] [ 3 5 0 -2 -13 ] now its easy to manipulate them to be echelon form
I just don't understand this.
[ 1 -2 -4 0 5 ] [ 0 4 3 3 1 ] [ 2 0 7 -1 -1 ] [ 3 5 0 -2 -13 ] try to continue this one tobe gaussian echelon form