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coolaidd
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You buy a house for $250,000 and it appreciates at a rate of 3% a year. How much will the house be worth after 3 years? Round to the nearest dollar.
 2 years ago
 2 years ago
coolaidd Group Title
You buy a house for $250,000 and it appreciates at a rate of 3% a year. How much will the house be worth after 3 years? Round to the nearest dollar.
 2 years ago
 2 years ago

This Question is Closed

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
250000(1.03)^3 = 273182
 2 years ago

coolaidd Group TitleBest ResponseYou've already chosen the best response.0
thanks! I have like 2more questions like this.. you think you can help?
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
I can tyr!
 2 years ago

coolaidd Group TitleBest ResponseYou've already chosen the best response.0
1) Find the amount of time it will take to double an investment of $400 with a rate of 4.5% compounded continuously. Round your answer to the nearest tenth. 2) Find the rate it would take to double an investment of $600 in 10 years if the rate is compounded continuously. Round your answer to the nearest tenth.
 2 years ago

coolaidd Group TitleBest ResponseYou've already chosen the best response.0
@tcarroll010
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
First, the formula for compounding continuously is: \[A = P \times e ^{0.045t}\]
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
\[800 = 400 \times e ^{0.045t}\] \[2 = e ^{0.045t}\]\[\ln 2 = \ln e ^{0.045t}\]\[\frac{ \ln 2 }{ 0.045 } = t\]
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
t = 15.4
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
For the second one,\[1200 = 600 \times e ^{(r)(10)}\] \[2 = e ^{10r}\]\[\ln 2 = \ln e ^{10r}\]\[\frac{ \ln 2 }{ 10 } = r = 0.0693\]
 2 years ago

coolaidd Group TitleBest ResponseYou've already chosen the best response.0
Thank you soo soo much!
 2 years ago
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