abp2u
Indefinite integration:
2x (x^2 + 1) ^4 dx



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abe.hassan2
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u = x^+1

abe.hassan2
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du = 2x dx

abe.hassan2
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dx= du/2x
So, u^4 du = u^5/5

abe.hassan2
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or, 1/5(x^2+1)^5

abp2u
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Thanks!