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two persons of equal weight are hanging by thier hands from the ends of a rope hung over a frictionless pulley. they begin to climb the ropes. one person can climb twice the speed of other wrt rope. who will get to the top first?
 one year ago
 one year ago
two persons of equal weight are hanging by thier hands from the ends of a rope hung over a frictionless pulley. they begin to climb the ropes. one person can climb twice the speed of other wrt rope. who will get to the top first?
 one year ago
 one year ago

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ShadowysBest ResponseYou've already chosen the best response.0
have you the free body diagram?
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.0
yes i have. but i dont seem to get where the speed factor will come in.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
the distance covered is not the same. if one climbs faster, the other guy might also climb a shorter distance.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.0
so will they get to the top together?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
:) you'll have to calculate that. they might.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.0
well i think i got it. without solving. since there is no external force momentum of the system is conserved. and since there masses are equal the rate at which they climb up the rope relative to ground is equal. hence they will reach at the same time. is that fine? correct me if i am wrong.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
yup, their velocity relative to the ground is equal.
 one year ago
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