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yrelhan4
 3 years ago
two persons of equal weight are hanging by thier hands from the ends of a rope hung over a frictionless pulley. they begin to climb the ropes. one person can climb twice the speed of other wrt rope. who will get to the top first?
yrelhan4
 3 years ago
two persons of equal weight are hanging by thier hands from the ends of a rope hung over a frictionless pulley. they begin to climb the ropes. one person can climb twice the speed of other wrt rope. who will get to the top first?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0have you the free body diagram?

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.0yes i have. but i dont seem to get where the speed factor will come in.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the distance covered is not the same. if one climbs faster, the other guy might also climb a shorter distance.

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.0so will they get to the top together?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0:) you'll have to calculate that. they might.

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.0well i think i got it. without solving. since there is no external force momentum of the system is conserved. and since there masses are equal the rate at which they climb up the rope relative to ground is equal. hence they will reach at the same time. is that fine? correct me if i am wrong.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup, their velocity relative to the ground is equal.
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