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yrelhan4
Group Title
two persons of equal weight are hanging by thier hands from the ends of a rope hung over a frictionless pulley. they begin to climb the ropes. one person can climb twice the speed of other wrt rope. who will get to the top first?
 2 years ago
 2 years ago
yrelhan4 Group Title
two persons of equal weight are hanging by thier hands from the ends of a rope hung over a frictionless pulley. they begin to climb the ropes. one person can climb twice the speed of other wrt rope. who will get to the top first?
 2 years ago
 2 years ago

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Shadowys Group TitleBest ResponseYou've already chosen the best response.0
have you the free body diagram?
 2 years ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
yes i have. but i dont seem to get where the speed factor will come in.
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
the distance covered is not the same. if one climbs faster, the other guy might also climb a shorter distance.
 2 years ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
so will they get to the top together?
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
:) you'll have to calculate that. they might.
 2 years ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.0
well i think i got it. without solving. since there is no external force momentum of the system is conserved. and since there masses are equal the rate at which they climb up the rope relative to ground is equal. hence they will reach at the same time. is that fine? correct me if i am wrong.
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.0
yup, their velocity relative to the ground is equal.
 2 years ago
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