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John_henderson

  • 3 years ago

1. Given that X=x(t) and y=Y(t) are two functions of time, t and they are related by the following equations. dx/dt - x +y=e^t x-dy/dt=0 by eliminatiing x=x(t) and its derivative show that : d^2y/dt^2- dy/dt+y = e^t 2. Use laplace transform to solve the resulting differential eqaution : d^2y/dt^2 - dy/dt +y = e^t conditions y(0)=1 and dy/dt=1 and t=0 3. Hence find an explicit form of x=x(t)

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  1. John_henderson
    • 3 years ago
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    im i supposed to diffrentiate the first part?

  2. John_henderson
    • 3 years ago
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    i dont have a clue how to start this ?

  3. John_henderson
    • 3 years ago
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    How can eliminate x(t)?

  4. John_henderson
    • 3 years ago
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    Any idea how?

  5. slaaibak
    • 3 years ago
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    First derive the second equation wrt time: dx/dt - d^2y/dt^2=0 Rewrite as: dx/dt = d^2y/dt^2 <---- 1 Now rewrite the second equation: x = dy/dt <----2 Now look at the first equation: dx/dt - x +y=e^t Sub in 1 and 2: d^2y/dt^2 - dy/dt + y = e^t which gives the desired result.

  6. slaaibak
    • 3 years ago
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    I've never done differential equations or laplace transformations, so I can't help on the second and third one, sorry

  7. John_henderson
    • 3 years ago
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    oh right i see, i think i can do question 2, but not sure about 3?

  8. slaaibak
    • 3 years ago
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    If you give me the answer to the second one, I can try and figure out 3.

  9. John_henderson
    • 3 years ago
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    let me work on ...

  10. mahmit2012
    • 3 years ago
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    |dw:1354568179841:dw|

  11. mahmit2012
    • 3 years ago
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    |dw:1354568287483:dw|

  12. John_henderson
    • 3 years ago
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    Where did you get xcos from?

  13. mahmit2012
    • 3 years ago
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    |dw:1354568458794:dw|

  14. mahmit2012
    • 3 years ago
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    |dw:1354568607205:dw|

  15. John_henderson
    • 3 years ago
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    right so for part 3 you meant to solve in terms of x !

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