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haterofmathBest ResponseYou've already chosen the best response.0
\[\frac{ \sqrt{18} }{ \sqrt{36} }=\frac{ \sqrt{2} }{ 2 }\]
 one year ago

phiBest ResponseYou've already chosen the best response.1
yes. you can see it is true by factoring each number into its prime factors 18 is 2*9 = 2*3*3 36 is 2*18= 2*2*9= 2*2*3*3 when these are under a square root \[ \frac{\sqrt{2\cdot 3\cdot 3}}{\sqrt{2\cdot 2\cdot 3 \cdot 3} }\] you can "pull out" pairs. in the top, 3*3 out of the square root becomes 3 in the bottom both 2 and 3 come out \[ \frac{3 \sqrt{2}}{2\cdot 3} \] we can divide top and bottom by 3 to simplify to \[ \frac{\sqrt{2}}{2} \]
 one year ago

phiBest ResponseYou've already chosen the best response.1
of course, if you know 6*6=36 you can just replace the bottom sqrt(36) with 6 right away.
 one year ago

haterofmathBest ResponseYou've already chosen the best response.0
so the question ask to simplify
 one year ago

phiBest ResponseYou've already chosen the best response.1
sqrt(2)/2 is as simple as it gets. you could write it as 1/sqrt(2) but people do not sqrt's in the denominator.
 one year ago

haterofmathBest ResponseYou've already chosen the best response.0
ok. so i have another problem...it says to multiply and simplify \[(3\sqrt{10}2\sqrt{2})^2=9824\sqrt{5}\]
 one year ago

phiBest ResponseYou've already chosen the best response.1
it looks like they gave you the answer. But to show how to do it, use FOIL on ( 3 sqrt(10)  2 sqrt(2) )* ( 3 sqrt(10)  2 sqrt(2) )
 one year ago

phiBest ResponseYou've already chosen the best response.1
here is an example of how to do this http://www.khanacademy.org/math/algebra/polynomials/v/multiplyingbinomialswithradicals
 one year ago

haterofmathBest ResponseYou've already chosen the best response.0
so it will just be \[(3\sqrt{10}2\sqrt{2})(3\sqrt{10}2\sqrt{2})=9824\sqrt{5}\]
 one year ago

phiBest ResponseYou've already chosen the best response.1
yes, but I think they want you to do the multiplication and get the answer they show you.
 one year ago

haterofmathBest ResponseYou've already chosen the best response.0
how would you do that?
 one year ago

phiBest ResponseYou've already chosen the best response.1
This video http://www.khanacademy.org/math/algebra/polynomials/v/multiplyingbinomials and the other one posted go into the details.
 one year ago
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