anonymous
  • anonymous
I need help ! Pleaseee Solve (x-2y +1) dx + (4x -3y -6) dy = 0
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
use green's theorem ( http://en.wikipedia.org/wiki/Green%27s_theorem )
anonymous
  • anonymous
Seriously??? can you tell me how to solve it?
anonymous
  • anonymous
It's been a while since i took calculus 3

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
then???
anonymous
  • anonymous
have you any idea, @Cynosure-EPR ?????
anonymous
  • anonymous
I'm sorry =( I do know how to do it but I'm rushed with a programming assignment (worth 40% of grade) due at midnight =(
anonymous
  • anonymous
ok no problem @Cynosure-EPR :) good luck for u :)
anonymous
  • anonymous
@zepp have u any idea??
zepp
  • zepp
Nope, I'm only at Calc II, sorry ):
anonymous
  • anonymous
ok np @zepp thank u for coming :)
anonymous
  • anonymous
|dw:1354582292989:dw|
anonymous
  • anonymous
\[(x-2y +1) dx + (4x -3y -6) dy = 0\]\[-(x-2y +1) dx = (4x -3y -6) dy \]\[\frac{ dy }{ dx }=\frac{ -(x-2y+1) }{ (4x -3y -6) }\]
anonymous
  • anonymous
Do you know how to do separation of variables? http://en.wikipedia.org/wiki/Separation_of_variables
anonymous
  • anonymous
This looks like a diff eq question
anonymous
  • anonymous
nvm, I don't think we can use that here
anonymous
  • anonymous
then ???? how to solve y?? i really know separation variable, but in this case that method cannot work,
anonymous
  • anonymous
yes.., i think so.., we cannot use that in this case.., :)
anonymous
  • anonymous
http://tutorial.math.lamar.edu/Classes/DE/Exact.aspx
anonymous
  • anonymous
My teacher skipped partial derivatives and that looks like what is needed for this problem. I'm going to tapout. Good luck
anonymous
  • anonymous
i see.., wonderful site for me.., thank u @ChmE,
sirm3d
  • sirm3d
solve the system of equation \[\large \left(\begin{matrix}x-2y+1=0 \\ 4x-3y-6=0\end{matrix}\right)\]
sirm3d
  • sirm3d
when you get the solution, say x0 and y0, use u = x - x0 and v = y - y0. try this @gerryliyana
anonymous
  • anonymous
ok.., i'll try
sirm3d
  • sirm3d
did you get this DE? \[\large (u-2v)du + (4u-3v)dv=0\] x changed to u, y changed to v, the constants +1 and -6 disappeared.
anonymous
  • anonymous
\[\left( \frac{ x - 2y + 1 }{ 4x -3y - 6 } \right) \times \left[ \frac{ 4 }{ 1 } \right]\] \[\left( \frac{ 4x - 8y + 4 }{ 4x - 3y -6 } \right) = 0\] \[\left( \frac{ 4x - 8y = -4 }{ 4x -3y= 6 } \right)\] -------------------------------------------- __ \[-8y -(-3y) = -10 \rightarrow y = 2\] \[4x - 3(2) = 6 \rightarrow x = 3\]
sirm3d
  • sirm3d
on the right track. now, u = x - 3 and v = y - 2
anonymous
  • anonymous
OMG..., my connection is lost, and I lost all my type, :(
sirm3d
  • sirm3d
hahaha. enter them a few equations at a time.
sirm3d
  • sirm3d
don't worry. you are not the first one.

Looking for something else?

Not the answer you are looking for? Search for more explanations.