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gerryliyana Group Title

I need help ! Pleaseee Solve (x-2y +1) dx + (4x -3y -6) dy = 0

  • one year ago
  • one year ago

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  1. xon1300 Group Title
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    use green's theorem ( http://en.wikipedia.org/wiki/Green%27s_theorem )

    • one year ago
  2. gerryliyana Group Title
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    Seriously??? can you tell me how to solve it?

    • one year ago
  3. xon1300 Group Title
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    It's been a while since i took calculus 3

    • one year ago
  4. gerryliyana Group Title
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    then???

    • one year ago
  5. gerryliyana Group Title
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    have you any idea, @Cynosure-EPR ?????

    • one year ago
  6. Cynosure-EPR Group Title
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    I'm sorry =( I do know how to do it but I'm rushed with a programming assignment (worth 40% of grade) due at midnight =(

    • one year ago
  7. gerryliyana Group Title
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    ok no problem @Cynosure-EPR :) good luck for u :)

    • one year ago
  8. gerryliyana Group Title
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    @zepp have u any idea??

    • one year ago
  9. zepp Group Title
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    Nope, I'm only at Calc II, sorry ):

    • one year ago
  10. gerryliyana Group Title
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    ok np @zepp thank u for coming :)

    • one year ago
  11. mahmit2012 Group Title
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    |dw:1354582292989:dw|

    • one year ago
  12. ChmE Group Title
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    \[(x-2y +1) dx + (4x -3y -6) dy = 0\]\[-(x-2y +1) dx = (4x -3y -6) dy \]\[\frac{ dy }{ dx }=\frac{ -(x-2y+1) }{ (4x -3y -6) }\]

    • one year ago
  13. ChmE Group Title
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    Do you know how to do separation of variables? http://en.wikipedia.org/wiki/Separation_of_variables

    • one year ago
  14. ChmE Group Title
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    This looks like a diff eq question

    • one year ago
  15. ChmE Group Title
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    nvm, I don't think we can use that here

    • one year ago
  16. gerryliyana Group Title
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    then ???? how to solve y?? i really know separation variable, but in this case that method cannot work,

    • one year ago
  17. gerryliyana Group Title
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    yes.., i think so.., we cannot use that in this case.., :)

    • one year ago
  18. ChmE Group Title
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    http://tutorial.math.lamar.edu/Classes/DE/Exact.aspx

    • one year ago
  19. ChmE Group Title
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    My teacher skipped partial derivatives and that looks like what is needed for this problem. I'm going to tapout. Good luck

    • one year ago
  20. gerryliyana Group Title
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    i see.., wonderful site for me.., thank u @ChmE,

    • one year ago
  21. sirm3d Group Title
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    solve the system of equation \[\large \left(\begin{matrix}x-2y+1=0 \\ 4x-3y-6=0\end{matrix}\right)\]

    • one year ago
  22. sirm3d Group Title
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    when you get the solution, say x0 and y0, use u = x - x0 and v = y - y0. try this @gerryliyana

    • one year ago
  23. gerryliyana Group Title
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    ok.., i'll try

    • one year ago
  24. sirm3d Group Title
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    did you get this DE? \[\large (u-2v)du + (4u-3v)dv=0\] x changed to u, y changed to v, the constants +1 and -6 disappeared.

    • one year ago
  25. gerryliyana Group Title
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    \[\left( \frac{ x - 2y + 1 }{ 4x -3y - 6 } \right) \times \left[ \frac{ 4 }{ 1 } \right]\] \[\left( \frac{ 4x - 8y + 4 }{ 4x - 3y -6 } \right) = 0\] \[\left( \frac{ 4x - 8y = -4 }{ 4x -3y= 6 } \right)\] -------------------------------------------- __ \[-8y -(-3y) = -10 \rightarrow y = 2\] \[4x - 3(2) = 6 \rightarrow x = 3\]

    • one year ago
  26. sirm3d Group Title
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    on the right track. now, u = x - 3 and v = y - 2

    • one year ago
  27. gerryliyana Group Title
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    OMG..., my connection is lost, and I lost all my type, :(

    • one year ago
  28. sirm3d Group Title
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    hahaha. enter them a few equations at a time.

    • one year ago
  29. sirm3d Group Title
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    don't worry. you are not the first one.

    • one year ago
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