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I need help ! Pleaseee
Solve
(x2y +1) dx + (4x 3y 6) dy = 0
 one year ago
 one year ago
I need help ! Pleaseee Solve (x2y +1) dx + (4x 3y 6) dy = 0
 one year ago
 one year ago

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xon1300Best ResponseYou've already chosen the best response.0
use green's theorem ( http://en.wikipedia.org/wiki/Green%27s_theorem )
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
Seriously??? can you tell me how to solve it?
 one year ago

xon1300Best ResponseYou've already chosen the best response.0
It's been a while since i took calculus 3
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
have you any idea, @CynosureEPR ?????
 one year ago

CynosureEPRBest ResponseYou've already chosen the best response.0
I'm sorry =( I do know how to do it but I'm rushed with a programming assignment (worth 40% of grade) due at midnight =(
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
ok no problem @CynosureEPR :) good luck for u :)
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
@zepp have u any idea??
 one year ago

zeppBest ResponseYou've already chosen the best response.0
Nope, I'm only at Calc II, sorry ):
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
ok np @zepp thank u for coming :)
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.1
dw:1354582292989:dw
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
\[(x2y +1) dx + (4x 3y 6) dy = 0\]\[(x2y +1) dx = (4x 3y 6) dy \]\[\frac{ dy }{ dx }=\frac{ (x2y+1) }{ (4x 3y 6) }\]
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
Do you know how to do separation of variables? http://en.wikipedia.org/wiki/Separation_of_variables
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
This looks like a diff eq question
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
nvm, I don't think we can use that here
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
then ???? how to solve y?? i really know separation variable, but in this case that method cannot work,
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
yes.., i think so.., we cannot use that in this case.., :)
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
http://tutorial.math.lamar.edu/Classes/DE/Exact.aspx
 one year ago

ChmEBest ResponseYou've already chosen the best response.0
My teacher skipped partial derivatives and that looks like what is needed for this problem. I'm going to tapout. Good luck
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
i see.., wonderful site for me.., thank u @ChmE,
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
solve the system of equation \[\large \left(\begin{matrix}x2y+1=0 \\ 4x3y6=0\end{matrix}\right)\]
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
when you get the solution, say x0 and y0, use u = x  x0 and v = y  y0. try this @gerryliyana
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
did you get this DE? \[\large (u2v)du + (4u3v)dv=0\] x changed to u, y changed to v, the constants +1 and 6 disappeared.
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
\[\left( \frac{ x  2y + 1 }{ 4x 3y  6 } \right) \times \left[ \frac{ 4 }{ 1 } \right]\] \[\left( \frac{ 4x  8y + 4 }{ 4x  3y 6 } \right) = 0\] \[\left( \frac{ 4x  8y = 4 }{ 4x 3y= 6 } \right)\]  __ \[8y (3y) = 10 \rightarrow y = 2\] \[4x  3(2) = 6 \rightarrow x = 3\]
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
on the right track. now, u = x  3 and v = y  2
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.0
OMG..., my connection is lost, and I lost all my type, :(
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
hahaha. enter them a few equations at a time.
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
don't worry. you are not the first one.
 one year ago
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