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gerryliyana

  • 2 years ago

I need help ! Pleaseee Solve (x-2y +1) dx + (4x -3y -6) dy = 0

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  1. xon1300
    • 2 years ago
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    use green's theorem ( http://en.wikipedia.org/wiki/Green%27s_theorem )

  2. gerryliyana
    • 2 years ago
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    Seriously??? can you tell me how to solve it?

  3. xon1300
    • 2 years ago
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    It's been a while since i took calculus 3

  4. gerryliyana
    • 2 years ago
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    then???

  5. gerryliyana
    • 2 years ago
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    have you any idea, @Cynosure-EPR ?????

  6. Cynosure-EPR
    • 2 years ago
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    I'm sorry =( I do know how to do it but I'm rushed with a programming assignment (worth 40% of grade) due at midnight =(

  7. gerryliyana
    • 2 years ago
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    ok no problem @Cynosure-EPR :) good luck for u :)

  8. gerryliyana
    • 2 years ago
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    @zepp have u any idea??

  9. zepp
    • 2 years ago
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    Nope, I'm only at Calc II, sorry ):

  10. gerryliyana
    • 2 years ago
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    ok np @zepp thank u for coming :)

  11. mahmit2012
    • 2 years ago
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    |dw:1354582292989:dw|

  12. ChmE
    • 2 years ago
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    \[(x-2y +1) dx + (4x -3y -6) dy = 0\]\[-(x-2y +1) dx = (4x -3y -6) dy \]\[\frac{ dy }{ dx }=\frac{ -(x-2y+1) }{ (4x -3y -6) }\]

  13. ChmE
    • 2 years ago
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    Do you know how to do separation of variables? http://en.wikipedia.org/wiki/Separation_of_variables

  14. ChmE
    • 2 years ago
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    This looks like a diff eq question

  15. ChmE
    • 2 years ago
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    nvm, I don't think we can use that here

  16. gerryliyana
    • 2 years ago
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    then ???? how to solve y?? i really know separation variable, but in this case that method cannot work,

  17. gerryliyana
    • 2 years ago
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    yes.., i think so.., we cannot use that in this case.., :)

  18. ChmE
    • 2 years ago
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    http://tutorial.math.lamar.edu/Classes/DE/Exact.aspx

  19. ChmE
    • 2 years ago
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    My teacher skipped partial derivatives and that looks like what is needed for this problem. I'm going to tapout. Good luck

  20. gerryliyana
    • 2 years ago
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    i see.., wonderful site for me.., thank u @ChmE,

  21. sirm3d
    • 2 years ago
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    solve the system of equation \[\large \left(\begin{matrix}x-2y+1=0 \\ 4x-3y-6=0\end{matrix}\right)\]

  22. sirm3d
    • 2 years ago
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    when you get the solution, say x0 and y0, use u = x - x0 and v = y - y0. try this @gerryliyana

  23. gerryliyana
    • 2 years ago
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    ok.., i'll try

  24. sirm3d
    • 2 years ago
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    did you get this DE? \[\large (u-2v)du + (4u-3v)dv=0\] x changed to u, y changed to v, the constants +1 and -6 disappeared.

  25. gerryliyana
    • 2 years ago
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    \[\left( \frac{ x - 2y + 1 }{ 4x -3y - 6 } \right) \times \left[ \frac{ 4 }{ 1 } \right]\] \[\left( \frac{ 4x - 8y + 4 }{ 4x - 3y -6 } \right) = 0\] \[\left( \frac{ 4x - 8y = -4 }{ 4x -3y= 6 } \right)\] -------------------------------------------- __ \[-8y -(-3y) = -10 \rightarrow y = 2\] \[4x - 3(2) = 6 \rightarrow x = 3\]

  26. sirm3d
    • 2 years ago
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    on the right track. now, u = x - 3 and v = y - 2

  27. gerryliyana
    • 2 years ago
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    OMG..., my connection is lost, and I lost all my type, :(

  28. sirm3d
    • 2 years ago
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    hahaha. enter them a few equations at a time.

  29. sirm3d
    • 2 years ago
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    don't worry. you are not the first one.

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