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if this was instead just: x + x
what would the answer be?

2x

correct, so now replace x by \(2^{70}\) and what do you get?

4^70...

not quite, you get two lots of \(2^{70}\) which can be written as:\[2\times2^{70}\]

you can now use the law of exponents to simplify this

e.g.:\[x^a\times x^b=x^{a+b}\]

use the fact that:\[2=2^1\]

ok i kinda get it

great! :)

its just confusing because i asumed that the answer would be 2^140

think of a simpler example:\[2^3=2\times2\times2\]

so:\[2\times2^3=2\times2\times2\times2=2^4=2^{1+3}\]

how would you do it with fractions though? like 2^1/3+2^1/3+2^1/3+2^1/3

same rules apply:\[2^a\times2^b=2^{a+b}\]even if a and b area fractions

you may find this helpful: http://www.mathsisfun.com/exponent.html

thanks alot :)