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math_proof

  • 2 years ago

Green's theorem circulation form. F=<0,x^2+y^2> on bounded circle x^2+y^2<1

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  1. math_proof
    • 2 years ago
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    do it in both integrals

  2. malevolence19
    • 2 years ago
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    I typed that wrong: \[L=0,M=x^2+y^2 \implies \frac{\partial M}{\partial x}=2x; \frac{\partial L}{\partial y}=0; \implies 2 \int\limits_0^{2 \pi}\int\limits_0^1 r^2 \cos(\phi) dr d \phi\] Which either way still equals zero.

  3. math_proof
    • 2 years ago
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    how did you oo so you used the cylindrical coordinates and made x=rcos(x)

  4. math_proof
    • 2 years ago
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    but it says to use 2 different integrals in green's theorem, im confused which is the second one. Like you know the green's theorem one formula equals alternative formula

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