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dakotajason27
Group Title
Evaluate the integral! From 0 to pi/3 of 4sec x tan x dx
 one year ago
 one year ago
dakotajason27 Group Title
Evaluate the integral! From 0 to pi/3 of 4sec x tan x dx
 one year ago
 one year ago

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dakotajason27 Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{0}^{\pi/3} 4\sec x \tan x\]
 one year ago

coolestkidd Group TitleBest ResponseYou've already chosen the best response.0
i am helpi u right noe
 one year ago

dakotajason27 Group TitleBest ResponseYou've already chosen the best response.0
Like i get the basic jist of integrals i just get stuck on finding the antiderivative
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
see if you can think of a function whose derivative is \(\sec(x)\tan(x)\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
or look in the book for the derivatives of trig functions. you will see it
 one year ago

coolestkidd Group TitleBest ResponseYou've already chosen the best response.0
i cant find the anser
 one year ago

dakotajason27 Group TitleBest ResponseYou've already chosen the best response.0
sec 4x and they just applied the chasin rule?
 one year ago

dakotajason27 Group TitleBest ResponseYou've already chosen the best response.0
chain*
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
easier than that
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if you take the derivative of \(\sec(4x)\) you will get \(4\sec(4x)\tan(4x)\) which is not at all what you want. just leave the constant alone and take \(4\sec(x)\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
plug in \(\frac{\pi}{3}\) plug in \(0\) and subtract actually forget 0 because \(\tan(0)=0\)
 one year ago

dakotajason27 Group TitleBest ResponseYou've already chosen the best response.0
ok perfect i can do it from here thanks :)
 one year ago

dakotajason27 Group TitleBest ResponseYou've already chosen the best response.0
answers 2 right?
 one year ago
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