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zaphodBest ResponseYou've already chosen the best response.0
http://screencast.com/t/N9H6p6CGYc
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
@satellite73 @Shadowys @RadEn
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
\(a\) is the amplitude. since this starts and 3 and goes up do 9, then comes back down to 3 and then to 3, the amplitude is 6
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
that is, the range is of length 12 from 3 to 9, so the amplitude is half of that, therefore \(a=6\)
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
IS THERE ANY OTHER METHOD TO SOLVE IT WITH EQUATIONS.
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
from your eyes you see that the period is \(\pi\) the period of \(\sin(bx)\) is \(\frac{2\pi}{b}\) so set \(\frac{2\pi}{b}=\pi\) and solve for \(b\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
no there are no equations here, you have to visualize, since you are given a picture
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
well there is an equation to find \(b\) . it is \[\frac{2\pi}{b}=\pi\] but you only know that the period is \(\pi\) from looking at the graph
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
and i know c, now can i substitute it in the main equation and find a?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
that is the entire point of this exercise, not to use equations, but to visualize the period, and amplitude from the picture
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
we know \(c=3\) because this is the graph of sine lifted up 3 units
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
can u explain why period of sin(bx) = 2pi/b
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
it is always the case that the period of \(\sin(bx)\) is \(\frac{2\pi}{b}\) we can think of it this way. since is periodic with period \(2\pi\) so it does everything on the interval \([0,2\pi)\) now if \(bx=0\) that means \(x=0\) and if \(bx=2\pi\) that means \(x=\frac{2\pi}{b}\) so that gives you the period
 one year ago

allamiroBest ResponseYou've already chosen the best response.0
sub x = pi then x = 2pi when x = pi y =3 when x = 2pi y = 9 then solve the equations
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
@satellite73 period is for one complete wave right, how come its 2 pi, it has to be pi
 one year ago

allamiroBest ResponseYou've already chosen the best response.0
when x = 0 y = 0 then solve the equations for a b and c
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
cn u show the working @allamiro
 one year ago

allamiroBest ResponseYou've already chosen the best response.0
dsregard the 2 pi thing = 9 just x = pi and x = 0
 one year ago

allamiroBest ResponseYou've already chosen the best response.0
what you mean show the work x = pi y = 3 3 = a sin ( b* pi ) + c x= 0 y = 0 0 = a sin ( b * 0 ) + c
 one year ago

allamiroBest ResponseYou've already chosen the best response.0
sorry again y = 3 when x = 0 I didnt focus at the graph
 one year ago

zaphodBest ResponseYou've already chosen the best response.0
ok how do u find b now.
 one year ago

allamiroBest ResponseYou've already chosen the best response.0
yes so now lets say 9 = a sin ( bx) + 3 the highest value for sin when sinx b = 1 so bx = pi /2 so from there a =6
 one year ago

allamiroBest ResponseYou've already chosen the best response.0
y = 3 when x = pi /2 3 = 6 sin ( b 2 pi ) + 3 6 sin ( 2 b pi) = 0 sin ( 2 b pi ) = sin ( 2b pi ) = sin ( pi ) b = 1/2
 one year ago

allamiroBest ResponseYou've already chosen the best response.0
y = 3 when x = 2pi * correctiion
 one year ago
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