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anonymous
 4 years ago
Please help...
anonymous
 4 years ago
Please help...

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@satellite73 @Shadowys @RadEn

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\(a\) is the amplitude. since this starts and 3 and goes up do 9, then comes back down to 3 and then to 3, the amplitude is 6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is, the range is of length 12 from 3 to 9, so the amplitude is half of that, therefore \(a=6\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0IS THERE ANY OTHER METHOD TO SOLVE IT WITH EQUATIONS.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0from your eyes you see that the period is \(\pi\) the period of \(\sin(bx)\) is \(\frac{2\pi}{b}\) so set \(\frac{2\pi}{b}=\pi\) and solve for \(b\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no there are no equations here, you have to visualize, since you are given a picture

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well there is an equation to find \(b\) . it is \[\frac{2\pi}{b}=\pi\] but you only know that the period is \(\pi\) from looking at the graph

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and i know c, now can i substitute it in the main equation and find a?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is the entire point of this exercise, not to use equations, but to visualize the period, and amplitude from the picture

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we know \(c=3\) because this is the graph of sine lifted up 3 units

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u explain why period of sin(bx) = 2pi/b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is always the case that the period of \(\sin(bx)\) is \(\frac{2\pi}{b}\) we can think of it this way. since is periodic with period \(2\pi\) so it does everything on the interval \([0,2\pi)\) now if \(bx=0\) that means \(x=0\) and if \(bx=2\pi\) that means \(x=\frac{2\pi}{b}\) so that gives you the period

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sub x = pi then x = 2pi when x = pi y =3 when x = 2pi y = 9 then solve the equations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@satellite73 period is for one complete wave right, how come its 2 pi, it has to be pi

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when x = 0 y = 0 then solve the equations for a b and c

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cn u show the working @allamiro

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dsregard the 2 pi thing = 9 just x = pi and x = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what you mean show the work x = pi y = 3 3 = a sin ( b* pi ) + c x= 0 y = 0 0 = a sin ( b * 0 ) + c

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry again y = 3 when x = 0 I didnt focus at the graph

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok how do u find b now.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes so now lets say 9 = a sin ( bx) + 3 the highest value for sin when sinx b = 1 so bx = pi /2 so from there a =6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y = 3 when x = pi /2 3 = 6 sin ( b 2 pi ) + 3 6 sin ( 2 b pi) = 0 sin ( 2 b pi ) = sin ( 2b pi ) = sin ( pi ) b = 1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y = 3 when x = 2pi * correctiion
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