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anonymous
 3 years ago
Compute and simplify the difference quotient
f(a+h)f(a)

h
g(x)=2x^2+14x 13
anonymous
 3 years ago
Compute and simplify the difference quotient f(a+h)f(a)  h g(x)=2x^2+14x 13

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this was already confusing enough without changing it to g(x)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0replace \(g\) by \(f\) it makes no difference, it is all algabra

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh ok. so it's like: 2(a+h)^2+14(a)13 over h?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have to subtract first

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well, first you have to expand, then you have to subtract

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\(g(a+h)= 2(a+h)^2+14(a+h)13\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0expand like 2a+2h.... and so on?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah it is \[2(a^2+2ah+h^2)+14a+14h13\] \[=2a^2+4ah+2h^2+14a+14h13\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0square first multiply by 2 second

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0from this you need to subtract \(2a^2+14a13\) so everything without an \(h\) will be gone

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then you can factor out an \(h\) from the remaining terms in the numerator, and cancel with the \(h\) in the denominator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you should be left with \[4ah +14h+2h^2\] before you divide after you divide you get \[4a+14\] and next week you will be able to do this problem instantly in your head

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, so I have 2a^2 +4ah + 2h^2 +14a +14h 13 and then I subtract 2a2+14a−13? how do I know to do that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\(2a^22a^2=0\) \(14a14a=0\) and \(13(13)=0\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0in other words, every term without an \(h\) is gone

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and that leaves me with 4ah + 2h^2 +14h

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, and now divide by \(h\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which is one of my multiple choice answers...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well, I dunno if I'll be able to do that in my head instantly, but if I can work it out, then I'll be ok at least haha. Thanks @satellite73
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