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 2 years ago
Compute and simplify the difference quotient
f(a+h)f(a)

h
g(x)=2x^2+14x 13
 2 years ago
Compute and simplify the difference quotient f(a+h)f(a)  h g(x)=2x^2+14x 13

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brandonloves
 2 years ago
Best ResponseYou've already chosen the best response.0this was already confusing enough without changing it to g(x)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1replace \(g\) by \(f\) it makes no difference, it is all algabra

brandonloves
 2 years ago
Best ResponseYou've already chosen the best response.0oh ok. so it's like: 2(a+h)^2+14(a)13 over h?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1you have to subtract first

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1well, first you have to expand, then you have to subtract

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\(g(a+h)= 2(a+h)^2+14(a+h)13\)

brandonloves
 2 years ago
Best ResponseYou've already chosen the best response.0expand like 2a+2h.... and so on?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1yeah it is \[2(a^2+2ah+h^2)+14a+14h13\] \[=2a^2+4ah+2h^2+14a+14h13\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1square first multiply by 2 second

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1from this you need to subtract \(2a^2+14a13\) so everything without an \(h\) will be gone

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1then you can factor out an \(h\) from the remaining terms in the numerator, and cancel with the \(h\) in the denominator

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1you should be left with \[4ah +14h+2h^2\] before you divide after you divide you get \[4a+14\] and next week you will be able to do this problem instantly in your head

brandonloves
 2 years ago
Best ResponseYou've already chosen the best response.0ok, so I have 2a^2 +4ah + 2h^2 +14a +14h 13 and then I subtract 2a2+14a−13? how do I know to do that?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\(2a^22a^2=0\) \(14a14a=0\) and \(13(13)=0\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1in other words, every term without an \(h\) is gone

brandonloves
 2 years ago
Best ResponseYou've already chosen the best response.0and that leaves me with 4ah + 2h^2 +14h

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1yes, and now divide by \(h\)

brandonloves
 2 years ago
Best ResponseYou've already chosen the best response.0which is one of my multiple choice answers...

brandonloves
 2 years ago
Best ResponseYou've already chosen the best response.0well, I dunno if I'll be able to do that in my head instantly, but if I can work it out, then I'll be ok at least haha. Thanks @satellite73
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