A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
What is the value of a for the attached circle in general form?
anonymous
 4 years ago
What is the value of a for the attached circle in general form?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0**no answer choices!! and idk how to solve :(

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1factor the equation using prefect squares

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like the one of the circle?? (which i find??) or the general form?

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1\[x^2+ax+y^2+by+c=0\] \[\left(x+\frac a2\right)^2a^2+y^2+by+c=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why whoops?? haha :P am i not seeing something ur seeing??

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1(i forgot to square ) (fixed now)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh okay i see :P so what do i do now?

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1factor the y terms using the same technique , then move the three constants outside the brackets to the right hand side

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(x+a/x)^2=(a+y+by)^2 ?? did i do that right?? :/ idk...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oops i forgot the +c... so like this?? (x+a/x)^2=(a+y+by)^2+c ??? idk :(

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1\[\left(x+\frac a2\right)^2a^2+y^2+by+c=0\] \[\left(x+\frac a2\right)^2a^2+\left(y+\frac b2\right)^2b^2+c=0\] \[\left(x+\frac a2\right)^2+\left(y+\frac b2\right)^2=a^2+b^2c\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay :P but how do i solve for a?

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1compair to the general form of a circle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1354600365624:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or the one in my question?

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1354600399190:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh sorry! i meant  haha :P so do i refer to that one?? or the one in my problem? this one?dw:1354600447714:dw

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1354600492668:dw

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1now look at the graph

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay so (h,k) center=(4,2) and radius=2 ???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that right?? but how do i get the value of a from that?

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.1\[\left(x+\frac a2\right)^2+\left(y+\frac b2\right)^2=a^2+b^2c\] \[\left(xh\right)^2+\left(yk\right)^2=r^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so a=2 ?? is that right?? my answer is 2??

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.0center=(4,2) > h = 4, k = 2 radius=2 > r = 2 (xh)^2 + (yk)^2 = r^2 (x(4))^2 + (y2)^2 = 2^2 (x+4)^2 + (y2)^2 = 4 Now get this equation into x^2 + y^2 + ax + by + c = 0 form

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, lemme give this a shot hahaha idk how close ill get tho!!! x^2 + y^2 + 4^2  2^2  4 = 0 ??? idk haha :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that right?? or even close?? :/

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.0no that's not correct

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.0(xh)^2 + (yk)^2 = r^2 (x(4))^2 + (y2)^2 = 2^2 (x+4)^2 + (y2)^2 = 4 x^2 + 8x + 16 + y^2  4y + 16 = 4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0aww darn :( okay so i simplify that right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0kk so i get this? x^2 + 8x + 16 + y^2  4y + 16 = 4 = x^2 + y^2 +8x 4y +12 = 0 ??

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.016+164 isn't 12

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh theres another 16!! i didn't see that! my bad!!! so i get this?? x^2 + y^2 +8x 4y + 28 = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0kk so a=8 then?? my answer is 8? :O

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0awesome :) thanks so much for all of ur help @UnkleRhaukus and @jim_thompson5910 :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.