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anonymous
 3 years ago
What is the value of a for the attached circle in general form?
anonymous
 3 years ago
What is the value of a for the attached circle in general form?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0**no answer choices!! and idk how to solve :(

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1factor the equation using prefect squares

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0like the one of the circle?? (which i find??) or the general form?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[x^2+ax+y^2+by+c=0\] \[\left(x+\frac a2\right)^2a^2+y^2+by+c=0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why whoops?? haha :P am i not seeing something ur seeing??

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1(i forgot to square ) (fixed now)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh okay i see :P so what do i do now?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1factor the y terms using the same technique , then move the three constants outside the brackets to the right hand side

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(x+a/x)^2=(a+y+by)^2 ?? did i do that right?? :/ idk...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oops i forgot the +c... so like this?? (x+a/x)^2=(a+y+by)^2+c ??? idk :(

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[\left(x+\frac a2\right)^2a^2+y^2+by+c=0\] \[\left(x+\frac a2\right)^2a^2+\left(y+\frac b2\right)^2b^2+c=0\] \[\left(x+\frac a2\right)^2+\left(y+\frac b2\right)^2=a^2+b^2c\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh okay :P but how do i solve for a?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1compair to the general form of a circle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354600365624:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or the one in my question?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354600399190:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh sorry! i meant  haha :P so do i refer to that one?? or the one in my problem? this one?dw:1354600447714:dw

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354600492668:dw

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1now look at the graph

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so (h,k) center=(4,2) and radius=2 ???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is that right?? but how do i get the value of a from that?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[\left(x+\frac a2\right)^2+\left(y+\frac b2\right)^2=a^2+b^2c\] \[\left(xh\right)^2+\left(yk\right)^2=r^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so a=2 ?? is that right?? my answer is 2??

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0center=(4,2) > h = 4, k = 2 radius=2 > r = 2 (xh)^2 + (yk)^2 = r^2 (x(4))^2 + (y2)^2 = 2^2 (x+4)^2 + (y2)^2 = 4 Now get this equation into x^2 + y^2 + ax + by + c = 0 form

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, lemme give this a shot hahaha idk how close ill get tho!!! x^2 + y^2 + 4^2  2^2  4 = 0 ??? idk haha :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is that right?? or even close?? :/

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0no that's not correct

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0(xh)^2 + (yk)^2 = r^2 (x(4))^2 + (y2)^2 = 2^2 (x+4)^2 + (y2)^2 = 4 x^2 + 8x + 16 + y^2  4y + 16 = 4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0aww darn :( okay so i simplify that right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0kk so i get this? x^2 + 8x + 16 + y^2  4y + 16 = 4 = x^2 + y^2 +8x 4y +12 = 0 ??

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.016+164 isn't 12

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh theres another 16!! i didn't see that! my bad!!! so i get this?? x^2 + y^2 +8x 4y + 28 = 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0kk so a=8 then?? my answer is 8? :O

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0awesome :) thanks so much for all of ur help @UnkleRhaukus and @jim_thompson5910 :)
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