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24: find Point of Inflection and discuss concavity of graph of func.
40: find all relative extrema, use 2nd derivative test where applicable.
58: Water is running into the vase shown @ a constant rate.
(a) graph depth of water in vase as a function of time.
(b) Does the function have any Extrema? Explain.
(c) Interpret the PI (Point of Inflection) of the graph of d.
 one year ago
 one year ago
24: find Point of Inflection and discuss concavity of graph of func. 40: find all relative extrema, use 2nd derivative test where applicable. 58: Water is running into the vase shown @ a constant rate. (a) graph depth of water in vase as a function of time. (b) Does the function have any Extrema? Explain. (c) Interpret the PI (Point of Inflection) of the graph of d.
 one year ago
 one year ago

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LotusWingsBest ResponseYou've already chosen the best response.0
@Shadowys can you help please? :O
 one year ago

LotusWingsBest ResponseYou've already chosen the best response.0
Or anyone really :P
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
lol, um, meanwhile, can you type the original eq.?
 one year ago

LotusWingsBest ResponseYou've already chosen the best response.0
#24: f(x) = sinx+cosx [0, 2Pi] #40: f(x) 2sinx + cos2x [0, 2Pi] I think mostly i'm having issues with just finding the derivative of trig functions. Oh, and my friend helped me with number 58 so it's all cool.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
for question 40, for the test, you let f'(x) = 0 and solve for x. then, you apply the xvalues into f''(x) to test for maxima or minima
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
point of inflexion in 24 is found by letting f''(x)=0. also, you'll need the double angle formulas.
 one year ago

LotusWingsBest ResponseYou've already chosen the best response.0
yeah, i know how to = 0 but I don't know how to solve the trig to find the x :(
 one year ago

LotusWingsBest ResponseYou've already chosen the best response.0
dw:1354600377935:dw
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
lol okay, i'll do one as an example. \(sin x cos x=0\) \(cos x+ sin x=0\) applying the \(Rcos(x\alpha)\) form, where \(R=\sqrt{1+1}\), \(\alpha = tan^{1} 1=\pi/4\) \(\sqrt2 cos (x\pi/4)=0\) solve for x.
 one year ago

LotusWingsBest ResponseYou've already chosen the best response.0
i don't think i've ever seen the Rcos(x−α) form before. :O
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
hmm, another way is letting sin x = cos(pi\2 x) but this is much more complicated, but yes, this is the way to solve these type of eqs. for angles with the same cosine, i.e. \(\cos \theta= \cos \alpha\),\( \theta = 2n\pi \pm \alpha\)
 one year ago

LotusWingsBest ResponseYou've already chosen the best response.0
okay, thanks for your help!
 one year ago
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