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how do i find tan sqrt3/3?

Mathematics
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\[\tan \sqrt{3}/3\]
sorry, tan (theta) sqrt3/3
tan theta = sqrt 3 /3 ?

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Other answers:

yeah, there are aparently 6 solutions
like a formula solution
how to you find theta you mean? use arctan aka tan^-1
well 5pi/6 is one of the solutions so how would i write a formula solution?
sqrt3/3 = sqrt3/(sqrt3)^2 = 1/sqrt3 tan theta=1/sqrt3 so the answer is 30
pi/6
(1/6)*Pi and there ar an infinite amnt of solotions. Cuzz it is a trig function.
other wise just use calc in radian mode to get tan(3√/3)=0.6513878868
well thats not what im looking for, thank you. the answer on the back of my book says theta=5pi/6+kpi and i dont know how they got that answer
the + kpi just means that every k_pi it repeats.
how do you get 5pi/6?
well when I and edwardp did it we used calculators to find arctan and it gave us (1/6)*Pi which is pi/6 Put since it is repeating. I assume that 5pi/6 is also an answer. Just my guess.
oh ok
thanks
https://www.google.com/search?q=tan+x&rlz=1C1CHFX_enUS470US470&oq=tan+x&aqs=chrome.0.57j0l2j60j0j62.3764&sugexp=chrome,mod=1&sourceid=chrome&ie=UTF-8#hl=en&safe=off&tbo=d&rlz=1C1CHFX_enUS470US470&sclient=psy-ab&q=tan+x%2C+(1%2F3)*sqrt(3)&oq=tan+x%2C+(1%2F3)*sqrt(3)&gs_l=serp.3...43592.44285.1.44735.3.3.0.0.0.0.140.398.0j3.3.0.les%3Bcrnk_timediscounta..0.0...1c.1.oDEAZrLQsEY&psj=1&bav=on.2,or.r_gc.r_pw.r_cp.r_qf.&fp=590195a7cf0fc162&bpcl=39580677&biw=1422&bih=776 look at graph. See how it intercepts every pi?
yeah

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