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1. Which two points lie on a line with slope 2/3? use: m=(y2-y1)/(x2-x1) and plug in m which is slope and see which of the choices satisfies the equation 2/3=(y2-y1)/(x2-x1) It is (–3, 2) and (0, 4) (2-4)/(-3-0)=-2/-3=2/3 :)
It's still confusing o.O
do you go to connections academy
No but my schooling uses the same things as connections academy such as connexus and stuff like that :)
i recogizne the test that why i would help but i need unit name
Oh Functions, Equations, and Graphs : Linear functions and slope intercept.
All you have to do for q 1 is use the slope formula which is. m=(y2-y1)/(x2-x1) where m is slope and it will be 2/3 y2 is 2nd y y1 is first y x2 is 2nd x x1 is 1st x and just start pluging in.
ohhhhhhhh okay. Got it.
ook :D 2. What is the slope of the line that passes through the given points? (6, –1) and (–3, –1) you use the same formula y2 is 2nd y y1 is first y x2 is 2nd x x1 is 1st x |dw:1354601772235:dw|
4. Write the equation in slope-intercept form. What are the slope and y-intercept? 3/4x + 4/5y = 4 I think you skipped number 3. But the above is just solve for y and you effectively put it in y intercept form.
Thank you so much!!! :) Uhm I skipped 3 because I already got that one :P But thank you!
De nada :)
Woaaaa wait I still kinda don't get 4 o.O
simply solve for y 3/4x + 4/5y = 4 4/5y = 4-3/4x 4/5y = 5/4*(4-3/4x) y=5/4*(4-3/4x) y = -(15/16)*x+5 distriute 5/4 and rearrange
Oh okayyy! I tend to think things are more difficult than they really are. But thanks again :)
Just take it slow and read carefully :D All things are very simple that way.
Yea, sure thing :)