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brandonloves
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find indicated sum, difference, product or quotient: f(x)=16x^2; g(x)=4x
find (f+g)(x)
 2 years ago
 2 years ago
brandonloves Group Title
find indicated sum, difference, product or quotient: f(x)=16x^2; g(x)=4x find (f+g)(x)
 2 years ago
 2 years ago

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brandonloves Group TitleBest ResponseYou've already chosen the best response.0
g(f(x)) = 4(16x^2) right so far?
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
so then it's 4 16 +x^2
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
and 12 +x^2
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
cool, now do I plug in that g(x) for f(x)= 16x^2
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
quite horrible, but just sub 4x into the x.
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
like 16 (4x)
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
\(16 (4x)^2\)
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
oh shoot, I forgot the exponent
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
16(4x)^2 is 16 (4x)(4x) which is 32 +8x+x^2
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
and then add that to the 12+x^2 from g(x)?
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
hmm, very close, but something's off isn't it?
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
16(4x)^2 is not 16 (4x)(4x) it's 16  (4x)(4x) though.
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
ohhh, that may fix it
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
yeah. something will cancel out.
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
yea, it left +8x x^2
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
but I still don't have it exactly right. I should be getting x^2 +x +12 I think, but I've got a 12
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
note that (f+g)(x)=16x^2 +4x
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
(fg)(x)=16x^2 (4x)
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
hmm, so what do I need to do to solve it now?
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
well, first, lol which are you doing? addition or subtraction?
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
well, it says f+g, so I would assume addition
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
so, simplify this one and you're done. (f+g)(x)=16x^2 +4x
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
16(12+x^2) +4(12+x^2)? I think I screwed it up
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
or is it 16(+8x x^2) +4(+8x x^2) I'm not too sure of anything anymore
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
you don't need sub anything, just simplify as it's (f+g)(x) =f(x)+g(x)
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
oh, cuz I've already done all that. duh.
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
but when I add them together, I only get 20, the x^2's cancel out
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
I have an option for the answer to be x^2x+20
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
add 16x^2 and 4x only.
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
ok, well, thats it, obviously. but what happened to the 8x and +/2x^2's? were those just wrong?
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
they weren't needed? :)
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
jesus christ. haha. well ok. sorry for being such a pain in the retrice thanks for the help though
 2 years ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
hmm, well thats an odd substitution for @$$.... whatever lol
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
lol you're welcome
 2 years ago
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