brandonloves
find indicated sum, difference, product or quotient: f(x)=16x^2; g(x)=4x
find (f+g)(x)



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brandonloves
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g(f(x)) = 4(16x^2) right so far?

Shadowys
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yes.

brandonloves
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so then it's 4 16 +x^2

brandonloves
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and 12 +x^2

Shadowys
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yup! :)

brandonloves
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cool, now do I plug in that g(x) for f(x)= 16x^2

Shadowys
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quite horrible, but just sub 4x into the x.

brandonloves
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like 16 (4x)

Shadowys
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\(16 (4x)^2\)

brandonloves
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oh shoot, I forgot the exponent

brandonloves
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16(4x)^2 is 16 (4x)(4x) which is 32 +8x+x^2

brandonloves
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and then add that to the 12+x^2 from g(x)?

brandonloves
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hmm, very close, but something's off isn't it?

Shadowys
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16(4x)^2 is not 16 (4x)(4x)
it's 16  (4x)(4x) though.

brandonloves
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ohhh, that may fix it

Shadowys
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yeah. something will cancel out.

brandonloves
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yea, it left +8x x^2

brandonloves
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but I still don't have it exactly right. I should be getting x^2 +x +12 I think, but I've got a 12

Shadowys
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note that (f+g)(x)=16x^2 +4x

Shadowys
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(fg)(x)=16x^2 (4x)

brandonloves
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hmm, so what do I need to do to solve it now?

Shadowys
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well, first, lol which are you doing? addition or subtraction?

brandonloves
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well, it says f+g, so I would assume addition

Shadowys
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so, simplify this one and you're done. (f+g)(x)=16x^2 +4x

brandonloves
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oh ok

brandonloves
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16(12+x^2) +4(12+x^2)? I think I screwed it up

brandonloves
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or is it 16(+8x x^2) +4(+8x x^2) I'm not too sure of anything anymore

Shadowys
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you don't need sub anything, just simplify as it's (f+g)(x) =f(x)+g(x)

brandonloves
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oh, cuz I've already done all that. duh.

brandonloves
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but when I add them together, I only get 20, the x^2's cancel out

brandonloves
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I have an option for the answer to be x^2x+20

Shadowys
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add 16x^2 and 4x only.

brandonloves
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ok, well, thats it, obviously. but what happened to the 8x and +/2x^2's? were those just wrong?

Shadowys
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they weren't needed? :)

brandonloves
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jesus christ. haha. well ok. sorry for being such a pain in the retrice thanks for the help though

brandonloves
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hmm, well thats an odd substitution for @$$.... whatever lol

Shadowys
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lol you're welcome