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brandonloves

  • 3 years ago

find indicated sum, difference, product or quotient: f(x)=16-x^2; g(x)=4-x find (f+g)(x)

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  1. brandonloves
    • 3 years ago
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    g(f(x)) = 4-(16-x^2) right so far?

  2. Shadowys
    • 3 years ago
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    yes.

  3. brandonloves
    • 3 years ago
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    so then it's 4 -16 +x^2

  4. brandonloves
    • 3 years ago
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    and -12 +x^2

  5. Shadowys
    • 3 years ago
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    yup! :)

  6. brandonloves
    • 3 years ago
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    cool, now do I plug in that g(x) for f(x)= 16-x^2

  7. Shadowys
    • 3 years ago
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    quite horrible, but just sub 4-x into the x.

  8. brandonloves
    • 3 years ago
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    like 16 -(4-x)

  9. Shadowys
    • 3 years ago
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    \(16 -(4-x)^2\)

  10. brandonloves
    • 3 years ago
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    oh shoot, I forgot the exponent

  11. brandonloves
    • 3 years ago
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    16-(4-x)^2 is 16 (-4-x)(-4-x) which is 32 +8x+x^2

  12. brandonloves
    • 3 years ago
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    and then add that to the -12+x^2 from g(x)?

  13. brandonloves
    • 3 years ago
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    hmm, very close, but something's off isn't it?

  14. Shadowys
    • 3 years ago
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    16-(4-x)^2 is not 16 (-4-x)(-4-x) it's 16 - (4-x)(4-x) though.

  15. brandonloves
    • 3 years ago
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    ohhh, that may fix it

  16. Shadowys
    • 3 years ago
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    yeah. something will cancel out.

  17. brandonloves
    • 3 years ago
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    yea, it left +8x -x^2

  18. brandonloves
    • 3 years ago
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    but I still don't have it exactly right. I should be getting -x^2 +x +12 I think, but I've got a -12

  19. Shadowys
    • 3 years ago
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    note that (f+g)(x)=16-x^2 +4-x

  20. Shadowys
    • 3 years ago
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    (f-g)(x)=16-x^2 -(4-x)

  21. brandonloves
    • 3 years ago
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    hmm, so what do I need to do to solve it now?

  22. Shadowys
    • 3 years ago
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    well, first, lol which are you doing? addition or subtraction?

  23. brandonloves
    • 3 years ago
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    well, it says f+g, so I would assume addition

  24. Shadowys
    • 3 years ago
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    so, simplify this one and you're done. (f+g)(x)=16-x^2 +4-x

  25. brandonloves
    • 3 years ago
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    oh ok

  26. brandonloves
    • 3 years ago
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    16-(12+x^2) +4-(12+x^2)? I think I screwed it up

  27. brandonloves
    • 3 years ago
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    or is it 16-(+8x -x^2) +4-(+8x -x^2) I'm not too sure of anything anymore

  28. Shadowys
    • 3 years ago
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    you don't need sub anything, just simplify as it's (f+g)(x) =f(x)+g(x)

  29. brandonloves
    • 3 years ago
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    oh, cuz I've already done all that. duh.

  30. brandonloves
    • 3 years ago
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    but when I add them together, I only get 20, the x^2's cancel out

  31. brandonloves
    • 3 years ago
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    I have an option for the answer to be -x^2-x+20

  32. Shadowys
    • 3 years ago
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    add 16-x^2 and 4-x only.

  33. brandonloves
    • 3 years ago
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    ok, well, thats it, obviously. but what happened to the 8x and +/-2x^2's? were those just wrong?

  34. Shadowys
    • 3 years ago
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    they weren't needed? :)

  35. brandonloves
    • 3 years ago
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    jesus christ. haha. well ok. sorry for being such a pain in the retrice thanks for the help though

  36. brandonloves
    • 3 years ago
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    hmm, well thats an odd substitution for @$$.... whatever lol

  37. Shadowys
    • 3 years ago
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    lol you're welcome

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