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find indicated sum, difference, product or quotient: f(x)=16x^2; g(x)=4x
find (f+g)(x)
 one year ago
 one year ago
find indicated sum, difference, product or quotient: f(x)=16x^2; g(x)=4x find (f+g)(x)
 one year ago
 one year ago

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brandonlovesBest ResponseYou've already chosen the best response.0
g(f(x)) = 4(16x^2) right so far?
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
so then it's 4 16 +x^2
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
cool, now do I plug in that g(x) for f(x)= 16x^2
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
quite horrible, but just sub 4x into the x.
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
oh shoot, I forgot the exponent
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
16(4x)^2 is 16 (4x)(4x) which is 32 +8x+x^2
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
and then add that to the 12+x^2 from g(x)?
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
hmm, very close, but something's off isn't it?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
16(4x)^2 is not 16 (4x)(4x) it's 16  (4x)(4x) though.
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
ohhh, that may fix it
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
yeah. something will cancel out.
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
yea, it left +8x x^2
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
but I still don't have it exactly right. I should be getting x^2 +x +12 I think, but I've got a 12
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
note that (f+g)(x)=16x^2 +4x
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
(fg)(x)=16x^2 (4x)
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
hmm, so what do I need to do to solve it now?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
well, first, lol which are you doing? addition or subtraction?
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
well, it says f+g, so I would assume addition
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
so, simplify this one and you're done. (f+g)(x)=16x^2 +4x
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
16(12+x^2) +4(12+x^2)? I think I screwed it up
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
or is it 16(+8x x^2) +4(+8x x^2) I'm not too sure of anything anymore
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
you don't need sub anything, just simplify as it's (f+g)(x) =f(x)+g(x)
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
oh, cuz I've already done all that. duh.
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
but when I add them together, I only get 20, the x^2's cancel out
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
I have an option for the answer to be x^2x+20
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
add 16x^2 and 4x only.
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
ok, well, thats it, obviously. but what happened to the 8x and +/2x^2's? were those just wrong?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
they weren't needed? :)
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
jesus christ. haha. well ok. sorry for being such a pain in the retrice thanks for the help though
 one year ago

brandonlovesBest ResponseYou've already chosen the best response.0
hmm, well thats an odd substitution for @$$.... whatever lol
 one year ago
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