Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ajprincess

  • 2 years ago

Please help:) A mass less spring hanging vertically, extends by 5cm when a mass M is attached to its lower and vertical oscillations are started by pulling the mass M downwards by another 5cm and then releasing it. i.Find the frequency of oscillation and the maximum velocity of the oscillating mass. ii.If a second mass of 300g is added to M the frequency of oscillation is reduced to half the previous value. Find M.

  • This Question is Closed
  1. amini
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i. Omega= g/0.05 Hertz ii. M=100gr

  2. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It wud be really better if u show the steps @amini

  3. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1354605666317:dw||dw:1354605726585:dw| Am I right?

  4. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yup.

  5. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanx. so |dw:1354606338362:dw| right @shadowys?

  6. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Shadowys if u dnt mind pleae check my answer.

  7. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    where did the 2 pi go ?

  8. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2pi comes only when we find f right?

  9. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh. you're not using \(v=\frac{2\pi}{T}\) the answers are different though...

  10. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry. but \(\omega\) is only equal to (\frac{2\pi}{T}\). Isn't t? Maximum velocity is \(A\omega\)

  11. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    oh right. sorry. a lil rusty in SHM. right. v=rw so your answer's right.

  12. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    will the anwr for second part be this? |dw:1354608247839:dw|

  13. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Shadowys

  14. rajathsbhat
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i too am a little rusty on SHM but isn't the frequency of oscillation independent of the mass attached to the spring?

  15. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    wouldn't \(\omega' \)also change because of the increase in mass by 0.3g? @rajathsbhat that is for simple pendulum.

  16. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ya it will change.

  17. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it will be \(\omega'=\omega/2\).

  18. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1354615128244:dw|

  19. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    also the i didn't get (M+100) in f'

  20. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oops sorry. it has to be M+300.

  21. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    in g? not in SI units? lol though there wouldn't be much difference anyways. except for the mass part, i think it's okay.

  22. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1354616316357:dw| Am I right nw?

  23. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    the k will also change from your first eq.

  24. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    How to find it. New extension is nt given right?

  25. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    wait. sorry, i was wrong. k is a constant. lol eyes get blurry in a hurry.

  26. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so vat I hav done is right?

  27. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yup! :)

  28. ajprincess
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank u sooooooo much. @Shadowys. thanx to u too @rajathsbhat.

  29. Shadowys
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you're welcome :)

  30. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.