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kimdre10

  • 2 years ago

use the change of base formula to evaluate the expression log3 30

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  1. dpaInc
    • 2 years ago
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    is that \(\large log_330 \) ???

  2. kimdre10
    • 2 years ago
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    yesh

  3. slaaibak
    • 2 years ago
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    \[\log_3 30 = \log_3 (10 \times 3) = \log_3 10 + \log_3 3 = {\log_{10} 10 \over \log_{10}} + 1 = {1 \over \log_{10} 3 } +1 \]

  4. slaaibak
    • 2 years ago
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    Second last step should be: \[{\log_{10} 10 \over \log_{10} 3} + 1\]

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