Here's the question you clicked on:
kimdre10
use the change of base formula to evaluate the expression log3 30
is that \(\large log_330 \) ???
\[\log_3 30 = \log_3 (10 \times 3) = \log_3 10 + \log_3 3 = {\log_{10} 10 \over \log_{10}} + 1 = {1 \over \log_{10} 3 } +1 \]
Second last step should be: \[{\log_{10} 10 \over \log_{10} 3} + 1\]