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mayankdevnani
Group Title
A ball is released from the top of a tower of height 'h' meters. It takes 'T' seconds to reach the ground.What is the position of the ball in T/3 seconds?
a) h/9 metres from ground.
b)7h/9 m from ground.
c) 8h/9 m from ground.
d) 17h/18 m from ground.
 one year ago
 one year ago
mayankdevnani Group Title
A ball is released from the top of a tower of height 'h' meters. It takes 'T' seconds to reach the ground.What is the position of the ball in T/3 seconds? a) h/9 metres from ground. b)7h/9 m from ground. c) 8h/9 m from ground. d) 17h/18 m from ground.
 one year ago
 one year ago

This Question is Closed

Inspired Group TitleBest ResponseYou've already chosen the best response.1
ok, so using the position function, you see that \[\Delta y = .5 g t^2 \] and \[\Delta y = .5g (t/3)^2 = (.5 g t^2) / 9\] when t =t/3 so essentially, you have, hh/9= 8h/9
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
any short method very high level method.. @Inspired
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus @phi @Shadowys plz help
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
that method is quite quick and high level enough. :)
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
but i am in 9 class can you tell me step by step
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
the motion formula is \(S=ut + \frac{1}{2} at^2\), as u=0, and a=g, it simplifies to \(h=\frac{1}{2} aT^2\) when u=0, t=T/3, sub it in to get \(S= \frac{1}{2} a\frac{T^2}{9}=\frac{\frac{1}{2} aT^2}{9}=h/9\) subtracting the remaining height givens 8h/9dw:1354619702849:dw
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
i don't understand (sub it in t......)this line words are not so clear plz draw it.. @Shadowys
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
substitute the values u=0, and t=T/3 into S=ut+1/2at^2
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
dw:1354620517376:dw
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
next....
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
dw:1354620745066:dw
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
then,
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
then, since when T/3 > h/9 , then at that time, the object is h  h/9 above the ground, right?dw:1354620913980:dw
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
ohkkk!! thnx.. @Shadowys
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
you're welcome :)
 one year ago
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