Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
mayankdevnani
Group Title
A ball is released from the top of a tower of height 'h' meters. It takes 'T' seconds to reach the ground.What is the position of the ball in T/3 seconds?
a) h/9 metres from ground.
b)7h/9 m from ground.
c) 8h/9 m from ground.
d) 17h/18 m from ground.
 2 years ago
 2 years ago
mayankdevnani Group Title
A ball is released from the top of a tower of height 'h' meters. It takes 'T' seconds to reach the ground.What is the position of the ball in T/3 seconds? a) h/9 metres from ground. b)7h/9 m from ground. c) 8h/9 m from ground. d) 17h/18 m from ground.
 2 years ago
 2 years ago

This Question is Closed

Inspired Group TitleBest ResponseYou've already chosen the best response.1
ok, so using the position function, you see that \[\Delta y = .5 g t^2 \] and \[\Delta y = .5g (t/3)^2 = (.5 g t^2) / 9\] when t =t/3 so essentially, you have, hh/9= 8h/9
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
any short method very high level method.. @Inspired
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus @phi @Shadowys plz help
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
that method is quite quick and high level enough. :)
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
but i am in 9 class can you tell me step by step
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
the motion formula is \(S=ut + \frac{1}{2} at^2\), as u=0, and a=g, it simplifies to \(h=\frac{1}{2} aT^2\) when u=0, t=T/3, sub it in to get \(S= \frac{1}{2} a\frac{T^2}{9}=\frac{\frac{1}{2} aT^2}{9}=h/9\) subtracting the remaining height givens 8h/9dw:1354619702849:dw
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
i don't understand (sub it in t......)this line words are not so clear plz draw it.. @Shadowys
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
substitute the values u=0, and t=T/3 into S=ut+1/2at^2
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
dw:1354620517376:dw
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
next....
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
dw:1354620745066:dw
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
then,
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
then, since when T/3 > h/9 , then at that time, the object is h  h/9 above the ground, right?dw:1354620913980:dw
 2 years ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.0
ohkkk!! thnx.. @Shadowys
 2 years ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
you're welcome :)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.