Here's the question you clicked on:
mayankdevnani
urgent!!!!
If \[\sqrt{6}=2.449\] then the value of \[\frac{3\sqrt{2}}{2\sqrt{3}}\] is close to
time the numerator and denominator by \sqrt 2
options- a)1.225 b)0.816 c)0.613 d)2.449
howz that? @binary3i
\[[3 \sqrt{2}]/[2 \sqrt{3}] = [\sqrt{3} \sqrt{2}]/2=\sqrt{6}/2 \]
i don't understand..plz draw it
\[\frac{3\sqrt{2}}{2\sqrt{3}}=\frac{3\sqrt{2}}{2\sqrt{3}}\times\frac11\]\[\qquad\qquad=\frac{3\sqrt 2}{2\sqrt{3}}\times\frac{\sqrt2}{\sqrt2}\]\[\qquad\qquad=\frac{3\times2}{2\sqrt{6}}\]\[\qquad\qquad=\frac{3}{\sqrt{6}}\]\[\qquad\qquad\approx\frac{3}{2.5}\]\[\qquad\qquad=\frac{12}{10}\]\[\qquad\qquad=1.2\]
how did you get 12/10 @UnkleRhaukus
\[\frac{3}{2.5}=\frac3{2.5}\times\frac{1}{1}\]\[\qquad=\frac3{2.5}\times\frac{4}{4}\]\[\qquad=\frac{12}{10}\]
oh!!! i got it !! thank you very much @UnkleRhaukus and @binary3i
@binary3i 's solution is the superior solution.
it depends on the solution you understand
\[\large \frac{ 3\sqrt2 }{ 2\sqrt3 }\frac{ \sqrt3 }{ \sqrt3 }=\frac{ 3\sqrt 6 }{ 2(3) }=\frac{ \sqrt 6 }{ 2 }=\frac{2.449}{2}\]
ohkk thnx.. @sirm3d