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mayankdevnani

  • 2 years ago

urgent!!!!

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  1. mayankdevnani
    • 2 years ago
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    If \[\sqrt{6}=2.449\] then the value of \[\frac{3\sqrt{2}}{2\sqrt{3}}\] is close to

  2. binary3i
    • 2 years ago
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    2.449/2

  3. UnkleRhaukus
    • 2 years ago
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    time the numerator and denominator by \sqrt 2

  4. mayankdevnani
    • 2 years ago
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    options- a)1.225 b)0.816 c)0.613 d)2.449

  5. binary3i
    • 2 years ago
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    1.2245

  6. mayankdevnani
    • 2 years ago
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    howz that? @binary3i

  7. binary3i
    • 2 years ago
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    \[[3 \sqrt{2}]/[2 \sqrt{3}] = [\sqrt{3} \sqrt{2}]/2=\sqrt{6}/2 \]

  8. mayankdevnani
    • 2 years ago
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    i don't understand..plz draw it

  9. UnkleRhaukus
    • 2 years ago
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    \[\frac{3\sqrt{2}}{2\sqrt{3}}=\frac{3\sqrt{2}}{2\sqrt{3}}\times\frac11\]\[\qquad\qquad=\frac{3\sqrt 2}{2\sqrt{3}}\times\frac{\sqrt2}{\sqrt2}\]\[\qquad\qquad=\frac{3\times2}{2\sqrt{6}}\]\[\qquad\qquad=\frac{3}{\sqrt{6}}\]\[\qquad\qquad\approx\frac{3}{2.5}\]\[\qquad\qquad=\frac{12}{10}\]\[\qquad\qquad=1.2\]

  10. mayankdevnani
    • 2 years ago
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    how did you get 12/10 @UnkleRhaukus

  11. UnkleRhaukus
    • 2 years ago
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    \[\frac{3}{2.5}=\frac3{2.5}\times\frac{1}{1}\]\[\qquad=\frac3{2.5}\times\frac{4}{4}\]\[\qquad=\frac{12}{10}\]

  12. mayankdevnani
    • 2 years ago
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    oh!!! i got it !! thank you very much @UnkleRhaukus and @binary3i

  13. sirm3d
    • 2 years ago
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    @binary3i 's solution is the superior solution.

  14. binary3i
    • 2 years ago
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    it depends on the solution you understand

  15. sirm3d
    • 2 years ago
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    \[\large \frac{ 3\sqrt2 }{ 2\sqrt3 }\frac{ \sqrt3 }{ \sqrt3 }=\frac{ 3\sqrt 6 }{ 2(3) }=\frac{ \sqrt 6 }{ 2 }=\frac{2.449}{2}\]

  16. mayankdevnani
    • 2 years ago
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    ohkk thnx.. @sirm3d

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