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farukk
 3 years ago
???
farukk
 3 years ago
???

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farukk
 3 years ago
Best ResponseYou've already chosen the best response.0which is correct? i.e a+b\ab (after rationallization)a+b\ab * a+b\a+b or a+b\ab * ab\ab ?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354620267974:dw

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354620294927:dw

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0can it be ab rather than a+b?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1it would be equal but it wouldn't helpful in rationalisation

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354620486122:dw

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0how will we use power rule in this question?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1so the first step would be to remember that the the derivative of a sum , is the sum of derivatives

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\text d}{\text d x}(1+\sqrt{1x^2})=\frac{\text d}{\text d x}(1)+\frac{\text d}{\text d x}\left(\sqrt{1x^2}\right)\]

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0derivative of a constant will be 0

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1so the problem is much simpler now

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1can you remember the derivative of a function of a function?

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0to me it's start right now:)

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[ (f\circ g)'(x)=f(g(x))'=f'(g(x))g'(x)\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354621505691:dw

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1you have to multiply by the derivative of the the inside function

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354621612577:dw

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{\text d}{\text d x}(1+\sqrt{1x^2})\]\[=\frac{\text d}{\text d x}(1)+\frac{\text d}{\text d x}\left(\sqrt{1x^2}\right)\]\[=\frac{\text d}{\text d x}\left(\sqrt{1x^2}\right)\] \[\qquad\frac{\text d}{\text dx}f(g(x))=(f\circ g)'(x)=g'(x)f'(g(x))\]\[\qquad f(x)= x^{1/2}\qquad f'(x)=\frac12x^{1/2}\]\[\qquad g(x)=1x^2\qquad g'(x)=2x\] \[=2x\times\frac12(1x^2)^{1/2}\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1i know this stuff is tricky, can you tell me where about you are having trouble

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0it is but u have solved it thank u so much!!

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1yeah but do understand the chain rule/,

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0no will be tomorow in college

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0hey did you use chain rule?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1the chain rule for the derivative of a function of a function \[(f\circ g)'(x)=g'(x)f'(g(x))\]

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0is there any other way for this question except chain rule?

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0u didt use power rule? did u?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1i used the power fule to find f '(x) and g'((x)

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1watch this video , skip the first 5 minutes http://www.khanacademy.org/math/calculus/differentialcalculus/e/chain_rule_1

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0actually i have solved all my questions except this one in quite a simple way

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1did you get the right answers?

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0i'm solving questions using theorems

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1well you will have to learn the chain rule

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1this is the link i ment http://www.khanacademy.org/math/calculus/differentialcalculus/v/thechainrule?exid=chain_rule_1

farukk
 3 years ago
Best ResponseYou've already chosen the best response.0mistake* 2x\ 2 sqrt 1  x square

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1you can cancel the two
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