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khal

hi, im trying to figure an equation for my fish feeding ratio. how would you write an equation that doubles the feeding rate for every 10 degrees of temperature, starting at 20C

  • one year ago
  • one year ago

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  1. Shadowys
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    lol this reminds me of a computer program i wrote. let the rate, R(t) be a function of t, the temperature. in this case, for every 10 degrees increase, it will increase by two fold. \(R(t) = 2(\frac{n-20}{10})t= \frac{(n-20)t}{5}\) where n>20

    • one year ago
  2. khal
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    thank you very much! should make every day feeding much easier

    • one year ago
  3. Shadowys
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    lol you're welcome :) you program the feeder? lol

    • one year ago
  4. khal
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    im feeding manually, but this tank is running on high density, fish are still young so its not too crucial, but im trying to get the best growth without compromising water quality, total biomass * 10% of average weight at 20C, function should help me keep them just under satiation without generating hydrogen sulfide or nh3-nh4.

    • one year ago
  5. Shadowys
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    oh. Wow maths in action. lol

    • one year ago
  6. khal
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    i have yet to rig a feeder and a thermometer together, not quite yet :P

    • one year ago
  7. Shadowys
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    lol good luck anyways. :) i'm going to take this to my student who complain that maths are useless. lol

    • one year ago
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