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Find the vertices and locate the foci for the hyperbola whose equation is given.
49x^2  100y^2 = 4900
 one year ago
 one year ago
Find the vertices and locate the foci for the hyperbola whose equation is given. 49x^2  100y^2 = 4900
 one year ago
 one year ago

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ShadowysBest ResponseYou've already chosen the best response.0
as this is a normal hyperbola, no translation, so to find the vertices, just find the xintercept.
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
then change the hyperbola to standard form and use "a" and "b" to find e. the foci are \((\pm ae,0)\)
 one year ago

alyssababy7Best ResponseYou've already chosen the best response.0
My options: A. vertices: ( 10, 0), ( 10, 0) ; foci: (square root of 51, 0), (square root of 51, 0) B. vertices: ( 10, 0), ( 10, 0) ; foci: (square root of 149, 0), (square root of 149, 0) C. vertices: ( 7, 0), ( 7, 0) ; foci: (square root of 149, 0), (square root of 149, 0) D. vertices: (0, 10), (0, 10) ; foci: (0, square root of 149), (0, square root of 149)
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
I believe you've solved the intercepts?
 one year ago

alyssababy7Best ResponseYou've already chosen the best response.0
thank you very much
 one year ago
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