The 4 kg head of a sledgehammer is moving at 6 m/s when it strikes a spike driving it into a log. The duration of the impact is 2 ms. Find the time average of the impact force.

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The 4 kg head of a sledgehammer is moving at 6 m/s when it strikes a spike driving it into a log. The duration of the impact is 2 ms. Find the time average of the impact force.

Physics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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impulse is the change in momentum
Yes, but where does impulse come here?
It's basic newton's second law. \[F=\frac{m(v-u)}{t}\] You know m, v (=0), u and t.

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What do you mean by time average of impact force?
@rajathsbhat you have given the way to find the force, but that is not what they are asking here.
hmm i just noticed that.....i'm not too sure of what means though...
*what it means
Please help, this sum has been frustrating me for hours .... don't even know what it means ...
perhaps it's simply F/t?

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