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ethompsonn
Solve |x| + 7 < 4. {x | x < -11 or x > -3} {x | -3 < x < 3} Ø
subtract 7 from both sides first then since the right is negative, but the absolute value is never negative, there is no solution
abs(x)+7 is less than 4 abs(x) is less than 4 - 7 abs(x) is less than -3 therefore, x is less than plus or minus 3