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alyssababy7
Group Title
Find the standard form of the equation of the ellipse satisfying the given conditions. Foci: (0, 2), (0, 2); yintercepts: 5 and 5
 one year ago
 one year ago
alyssababy7 Group Title
Find the standard form of the equation of the ellipse satisfying the given conditions. Foci: (0, 2), (0, 2); yintercepts: 5 and 5
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
since the foci are at \((0,2)\) and \((0,2)\) the center is at the origin, so at least we know it looks like \[\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
since the vertices are at \((0,5)\) and \((0,5)\) we know \(b=5\) and so \(b^2=25\)
 one year ago

alyssababy7 Group TitleBest ResponseYou've already chosen the best response.0
Thank you
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
we still need \(a^2\) but since \(2^2=b^2a^2\) we can solve for it
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\(a^2=254=21\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
let me make sure this is right before i tell you something silly
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yes, i think this works, i.e. the answer would be \[\frac{x^2}{21}+\frac{y^2}{25}=1\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
lets check it http://www.wolframalpha.com/input/?i=ellipse+x^2%2F21%2By^2%2F25%3D1
 one year ago

alyssababy7 Group TitleBest ResponseYou've already chosen the best response.0
i had a multiple choice answer, and when you told me 25 was b^2, it was the only option. you are right, it is x^2/21 + y^2/25 = 1
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
oh, hiding that information... well it works in any case
 one year ago
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