## anonymous 3 years ago Convert the equation to the standard form for a hyperbola by completing the square on x and y. y^2 - 25x^2 + 4y + 50x - 46 = 0

1. anonymous

lol another multiple choice?

2. anonymous

Yes A. (x+2)^2/25 - (y-1)^2 = 1 B. (x-1)^2 - (x+2)^2/25 = 1 C. (x+2)^2/25 - (x-1)^2 = 1

3. anonymous

ok well that makes it much easier

4. anonymous

actually there must be something wrong here, because the $$y^2$$ term comes first

5. anonymous

$y^2 - 25x^2 + 4y + 50x - 46 = 0$

6. anonymous

these are my only options :/

7. anonymous

if the last one is really $\frac{(y+2)^2}{25}-(x-1)^2=1$ then go with that one

8. anonymous

thank you, i'm going to go with it.