Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
alyssababy7
Group Title
Convert the equation to the standard form for a hyperbola by completing the square on x and y.
y^2  25x^2 + 4y + 50x  46 = 0
 one year ago
 one year ago
alyssababy7 Group Title
Convert the equation to the standard form for a hyperbola by completing the square on x and y. y^2  25x^2 + 4y + 50x  46 = 0
 one year ago
 one year ago

This Question is Closed

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
lol another multiple choice?
 one year ago

alyssababy7 Group TitleBest ResponseYou've already chosen the best response.0
Yes A. (x+2)^2/25  (y1)^2 = 1 B. (x1)^2  (x+2)^2/25 = 1 C. (x+2)^2/25  (x1)^2 = 1
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
ok well that makes it much easier
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
actually there must be something wrong here, because the \(y^2\) term comes first
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[y^2  25x^2 + 4y + 50x  46 = 0 \]
 one year ago

alyssababy7 Group TitleBest ResponseYou've already chosen the best response.0
these are my only options :/
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if the last one is really \[\frac{(y+2)^2}{25}(x1)^2=1\] then go with that one
 one year ago

alyssababy7 Group TitleBest ResponseYou've already chosen the best response.0
thank you, i'm going to go with it.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.