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alyssababy7 Group Title

Convert the equation to the standard form for a hyperbola by completing the square on x and y. y^2 - 25x^2 + 4y + 50x - 46 = 0

  • one year ago
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  1. satellite73 Group Title
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    lol another multiple choice?

    • one year ago
  2. alyssababy7 Group Title
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    Yes A. (x+2)^2/25 - (y-1)^2 = 1 B. (x-1)^2 - (x+2)^2/25 = 1 C. (x+2)^2/25 - (x-1)^2 = 1

    • one year ago
  3. satellite73 Group Title
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    ok well that makes it much easier

    • one year ago
  4. satellite73 Group Title
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    actually there must be something wrong here, because the \(y^2\) term comes first

    • one year ago
  5. satellite73 Group Title
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    \[y^2 - 25x^2 + 4y + 50x - 46 = 0 \]

    • one year ago
  6. alyssababy7 Group Title
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    these are my only options :/

    • one year ago
  7. satellite73 Group Title
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    if the last one is really \[\frac{(y+2)^2}{25}-(x-1)^2=1\] then go with that one

    • one year ago
  8. alyssababy7 Group Title
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    thank you, i'm going to go with it.

    • one year ago
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