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alyssababy7

  • 2 years ago

Convert the equation to the standard form for a hyperbola by completing the square on x and y. y^2 - 25x^2 + 4y + 50x - 46 = 0

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  1. satellite73
    • 2 years ago
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    lol another multiple choice?

  2. alyssababy7
    • 2 years ago
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    Yes A. (x+2)^2/25 - (y-1)^2 = 1 B. (x-1)^2 - (x+2)^2/25 = 1 C. (x+2)^2/25 - (x-1)^2 = 1

  3. satellite73
    • 2 years ago
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    ok well that makes it much easier

  4. satellite73
    • 2 years ago
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    actually there must be something wrong here, because the \(y^2\) term comes first

  5. satellite73
    • 2 years ago
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    \[y^2 - 25x^2 + 4y + 50x - 46 = 0 \]

  6. alyssababy7
    • 2 years ago
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    these are my only options :/

  7. satellite73
    • 2 years ago
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    if the last one is really \[\frac{(y+2)^2}{25}-(x-1)^2=1\] then go with that one

  8. alyssababy7
    • 2 years ago
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    thank you, i'm going to go with it.

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