lilmommaannie
Solve by using the addition method.. Provide the solution set:
3x^2-5y^2=-33
2x^2+5y^2=35
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cwrw238
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when you add these 2 equations the terms in y disappear to give
5x^2 = 2
solve for x (there will be 2 solutions)
and plug these into one of the original equations to find the values of y.
cwrw238
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can you finish this or need more help?
lilmommaannie
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But now I have another one that the y values do not disappear?!
lilmommaannie
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And I dont get them!!
cwrw238
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ok post it
lilmommaannie
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2x^2-3y^2=-19
3x^2+2y^2-30
cwrw238
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ok
to do this you multiply equation 1 by 2 and equation 2 by 3 to give
4x^2 - 6y^2 = -38
9x^2 + 6y^2 = 90
is that = 30 in second equation?
lilmommaannie
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yes sorry
lol
cwrw238
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ok
so if you add these 2 equations you will eliminate y
cwrw238
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when you multiply equations be sure to multiply each term
lilmommaannie
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Thanks!!!!! I see it now!!!
cwrw238
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good
cwrw238
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that is what this website is for.
lilmommaannie
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So, would the answer be 2,3???