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Solve by using the addition method.. Provide the solution set: 3x^2-5y^2=-33 2x^2+5y^2=35

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when you add these 2 equations the terms in y disappear to give 5x^2 = 2 solve for x (there will be 2 solutions) and plug these into one of the original equations to find the values of y.
can you finish this or need more help?
But now I have another one that the y values do not disappear?!

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Other answers:

And I dont get them!!
ok post it
2x^2-3y^2=-19 3x^2+2y^2-30
ok to do this you multiply equation 1 by 2 and equation 2 by 3 to give 4x^2 - 6y^2 = -38 9x^2 + 6y^2 = 90 is that = 30 in second equation?
yes sorry lol
ok so if you add these 2 equations you will eliminate y
when you multiply equations be sure to multiply each term
Thanks!!!!! I see it now!!!
that is what this website is for.
So, would the answer be 2,3???

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