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lilmommaannie

  • 3 years ago

Solve by using the addition method.. Provide the solution set: 3x^2-5y^2=-33 2x^2+5y^2=35

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  1. cwrw238
    • 3 years ago
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    when you add these 2 equations the terms in y disappear to give 5x^2 = 2 solve for x (there will be 2 solutions) and plug these into one of the original equations to find the values of y.

  2. cwrw238
    • 3 years ago
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    can you finish this or need more help?

  3. lilmommaannie
    • 3 years ago
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    But now I have another one that the y values do not disappear?!

  4. lilmommaannie
    • 3 years ago
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    And I dont get them!!

  5. cwrw238
    • 3 years ago
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    ok post it

  6. lilmommaannie
    • 3 years ago
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    2x^2-3y^2=-19 3x^2+2y^2-30

  7. cwrw238
    • 3 years ago
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    ok to do this you multiply equation 1 by 2 and equation 2 by 3 to give 4x^2 - 6y^2 = -38 9x^2 + 6y^2 = 90 is that = 30 in second equation?

  8. lilmommaannie
    • 3 years ago
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    yes sorry lol

  9. cwrw238
    • 3 years ago
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    ok so if you add these 2 equations you will eliminate y

  10. cwrw238
    • 3 years ago
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    when you multiply equations be sure to multiply each term

  11. lilmommaannie
    • 3 years ago
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    Thanks!!!!! I see it now!!!

  12. cwrw238
    • 3 years ago
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    good

  13. cwrw238
    • 3 years ago
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    that is what this website is for.

  14. lilmommaannie
    • 3 years ago
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    So, would the answer be 2,3???

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