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AGummiBear55
 2 years ago
CHECK MY WORK, PLEASE! Solve: 16 < 3x + 1 < 4
16 < 3x + 1 < 4
16 < 3x + 1
1 to both sides
15<3x
/3 to both sides
5<x
3x + 1 < 4
1 to both sides
3x < 3
/3
x<1
Answer: 5<x and x<1
Did I do that right? I have a feeling I didn't.
AGummiBear55
 2 years ago
CHECK MY WORK, PLEASE! Solve: 16 < 3x + 1 < 4 16 < 3x + 1 < 4 16 < 3x + 1 1 to both sides 15<3x /3 to both sides 5<x 3x + 1 < 4 1 to both sides 3x < 3 /3 x<1 Answer: 5<x and x<1 Did I do that right? I have a feeling I didn't.

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zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0It's wrong. First of all, 16 cannot be less than 4.

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0Is there a mistake in the question?

AGummiBear55
 2 years ago
Best ResponseYou've already chosen the best response.0??? I thought with these types of problems you have to split them up from 16 < 3x + 1 < 4 to two equations; 16 < 3x +1 and 3x +1<4.
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