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AGummiBear55
Group Title
CHECK MY WORK, PLEASE! Solve: 16 < 3x + 1 < 4
16 < 3x + 1 < 4
16 < 3x + 1
1 to both sides
15<3x
/3 to both sides
5<x
3x + 1 < 4
1 to both sides
3x < 3
/3
x<1
Answer: 5<x and x<1
Did I do that right? I have a feeling I didn't.
 one year ago
 one year ago
AGummiBear55 Group Title
CHECK MY WORK, PLEASE! Solve: 16 < 3x + 1 < 4 16 < 3x + 1 < 4 16 < 3x + 1 1 to both sides 15<3x /3 to both sides 5<x 3x + 1 < 4 1 to both sides 3x < 3 /3 x<1 Answer: 5<x and x<1 Did I do that right? I have a feeling I didn't.
 one year ago
 one year ago

This Question is Closed

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
It's wrong. First of all, 16 cannot be less than 4.
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Is there a mistake in the question?
 one year ago

AGummiBear55 Group TitleBest ResponseYou've already chosen the best response.0
??? I thought with these types of problems you have to split them up from 16 < 3x + 1 < 4 to two equations; 16 < 3x +1 and 3x +1<4.
 one year ago
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