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AGummiBear55

  • 2 years ago

CHECK MY WORK, PLEASE! Solve: 16 < 3x + 1 < 4 16 < 3x + 1 < 4 16 < 3x + 1 -1 to both sides 15<3x /3 to both sides 5<x 3x + 1 < 4 -1 to both sides 3x < 3 /3 x<1 Answer: 5<x and x<1 Did I do that right? I have a feeling I didn't.

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  1. zordoloom
    • 2 years ago
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    It's wrong. First of all, 16 cannot be less than 4.

  2. zordoloom
    • 2 years ago
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    Is there a mistake in the question?

  3. AGummiBear55
    • 2 years ago
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    ??? I thought with these types of problems you have to split them up from 16 < 3x + 1 < 4 to two equations; 16 < 3x +1 and 3x +1<4.

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