A community for students. Sign up today!
Here's the question you clicked on:
← 55 members online
 0 viewing
 2 years ago
CHECK MY WORK, PLEASE! Solve: 16 < 3x + 1 < 4
16 < 3x + 1 < 4
16 < 3x + 1
1 to both sides
15<3x
/3 to both sides
5<x
3x + 1 < 4
1 to both sides
3x < 3
/3
x<1
Answer: 5<x and x<1
Did I do that right? I have a feeling I didn't.
 2 years ago
CHECK MY WORK, PLEASE! Solve: 16 < 3x + 1 < 4 16 < 3x + 1 < 4 16 < 3x + 1 1 to both sides 15<3x /3 to both sides 5<x 3x + 1 < 4 1 to both sides 3x < 3 /3 x<1 Answer: 5<x and x<1 Did I do that right? I have a feeling I didn't.

This Question is Closed

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0It's wrong. First of all, 16 cannot be less than 4.

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0Is there a mistake in the question?

AGummiBear55
 2 years ago
Best ResponseYou've already chosen the best response.0??? I thought with these types of problems you have to split them up from 16 < 3x + 1 < 4 to two equations; 16 < 3x +1 and 3x +1<4.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.