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Algebra
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|dw:1354640251797:dw| Please help me solve and show the work to help me solve other problems
\[16n^2-4=0\]?
\[16n^2=4\]\[n^2=\frac{4}{16}=\frac{1}{4}\]\[n=\sqrt{\frac{1}{4}}=\frac{1}{\sqrt{4}}=\pm\frac{1}{2}\]

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Other answers:

16n^2-4=0 yes that is correct
Is that a +1/-2 at the end of the equation
nope that means it has two solutions \(1/2\) and \(-1/2\)
I was not sure how you cam to your answer. Can you explain? Thanks you have been very helpful. Your awesome
well the first thing you want to do is isolate \(n^2\) so you first have add 4 to both sides, then divide both sides by 16. Now you have \(n^2\) on its own, so you have to take the square root of both sides to do that.
also I used \[\sqrt\frac{a}{b}=\frac{\sqrt{a}}{\sqrt{b}}\] to take the 1 out and \(\sqrt 4=\pm2\) that is = -2 and =2
Thank You, I wasnt sure about the 1. You have been very helpful. Thanks Again

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