anonymous
  • anonymous
I need someones help in solving a problem and showing the work so that I can solve the next few
Algebra
chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1354640251797:dw| Please help me solve and show the work to help me solve other problems
richyw
  • richyw
\[16n^2-4=0\]?
richyw
  • richyw
\[16n^2=4\]\[n^2=\frac{4}{16}=\frac{1}{4}\]\[n=\sqrt{\frac{1}{4}}=\frac{1}{\sqrt{4}}=\pm\frac{1}{2}\]

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anonymous
  • anonymous
16n^2-4=0 yes that is correct
anonymous
  • anonymous
Is that a +1/-2 at the end of the equation
richyw
  • richyw
nope that means it has two solutions \(1/2\) and \(-1/2\)
anonymous
  • anonymous
I was not sure how you cam to your answer. Can you explain? Thanks you have been very helpful. Your awesome
richyw
  • richyw
well the first thing you want to do is isolate \(n^2\) so you first have add 4 to both sides, then divide both sides by 16. Now you have \(n^2\) on its own, so you have to take the square root of both sides to do that.
richyw
  • richyw
also I used \[\sqrt\frac{a}{b}=\frac{\sqrt{a}}{\sqrt{b}}\] to take the 1 out and \(\sqrt 4=\pm2\) that is = -2 and =2
anonymous
  • anonymous
Thank You, I wasnt sure about the 1. You have been very helpful. Thanks Again

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