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anonymous
 3 years ago
I need someones help in solving a problem and showing the work so that I can solve the next few
anonymous
 3 years ago
I need someones help in solving a problem and showing the work so that I can solve the next few

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354640251797:dw Please help me solve and show the work to help me solve other problems

richyw
 3 years ago
Best ResponseYou've already chosen the best response.1\[16n^2=4\]\[n^2=\frac{4}{16}=\frac{1}{4}\]\[n=\sqrt{\frac{1}{4}}=\frac{1}{\sqrt{4}}=\pm\frac{1}{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.016n^24=0 yes that is correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is that a +1/2 at the end of the equation

richyw
 3 years ago
Best ResponseYou've already chosen the best response.1nope that means it has two solutions \(1/2\) and \(1/2\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I was not sure how you cam to your answer. Can you explain? Thanks you have been very helpful. Your awesome

richyw
 3 years ago
Best ResponseYou've already chosen the best response.1well the first thing you want to do is isolate \(n^2\) so you first have add 4 to both sides, then divide both sides by 16. Now you have \(n^2\) on its own, so you have to take the square root of both sides to do that.

richyw
 3 years ago
Best ResponseYou've already chosen the best response.1also I used \[\sqrt\frac{a}{b}=\frac{\sqrt{a}}{\sqrt{b}}\] to take the 1 out and \(\sqrt 4=\pm2\) that is = 2 and =2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank You, I wasnt sure about the 1. You have been very helpful. Thanks Again
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