haterofmath
find f'(x) for
f(x)=xe^2x



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nubeer
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you have to differentiate with the help of product rule.

haterofmath
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so it will be something like
\[xe ^{2x}(2)\]

nubeer
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yes its one part of derivative.. it's still incomplete uv'+vu'
you have just found uv'

haterofmath
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x(e^2x(2)+e^2x(1)

nubeer
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yup looks right now.

haterofmath
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ok. thanks