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haterofmath

  • 3 years ago

find f'(x) for f(x)=xe^2x

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  1. nubeer
    • 3 years ago
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    you have to differentiate with the help of product rule.

  2. haterofmath
    • 3 years ago
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    so it will be something like \[xe ^{2x}(2)\]

  3. nubeer
    • 3 years ago
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    yes its one part of derivative.. it's still incomplete uv'+vu' you have just found uv'

  4. haterofmath
    • 3 years ago
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    x(e^2x(2)+e^2x(1)

  5. nubeer
    • 3 years ago
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    yup looks right now.

  6. haterofmath
    • 3 years ago
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    ok. thanks

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