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ludwig457
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Suppose two wells are located 6 miles apart, and are drilled into a aquifer of average sand composition (i.e., hydraulic conductivity = 10 m/day). The water level in one of the wells is 40 feet, and the water level in the other well is 75 feet. If the aquifer is 3 miles wide and 50 feet deep, which of the following numbers is closest to the aquifer's actual discharge? (1 m = 3.28 feet)
 one year ago
 one year ago
ludwig457 Group Title
Suppose two wells are located 6 miles apart, and are drilled into a aquifer of average sand composition (i.e., hydraulic conductivity = 10 m/day). The water level in one of the wells is 40 feet, and the water level in the other well is 75 feet. If the aquifer is 3 miles wide and 50 feet deep, which of the following numbers is closest to the aquifer's actual discharge? (1 m = 3.28 feet)
 one year ago
 one year ago

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ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
Q= KA(H/L) Groundwater discharge can be calculated with the following equation: in which Q is an aquifer’s discharge, K is the aquifer’s hydraulic conductivity, A is the crosssectional area of the aquifer, H is the difference in elevation of the water table between two wells, and L is the horizontal distance between the two wells. (Note that H/L is the gradient, or slope, of the water table.) 150 m3/day 800 m3/day 1,200 m3/day 8,000 m3/day
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
H/L appears to be 35/(6*5280) feet
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
and I guess they want you to use a rectangle to approximate the CSA?
 one year ago

ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
yes 79,200ft
 one year ago

ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
\[Q=\frac{ (32.808ft)(79200ft ^{2})(35ft }{ 31680ft }\]
 one year ago

ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
then i converted to meters
 one year ago

ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
\[Q=\frac{ (9.997)(24140.16)(10.668) }{ 9656.06 }\]
 one year ago

ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
will ft^2 convert to meters^2?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
You seem to have an error there...
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
Better to convert the height and width to meters first... then find the CSA in meters^2
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
15.24 m * 4828 m
 one year ago

ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
73,578.72m^2
 one year ago

ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
((9.997)(73578.72)(10.668))/(9656.06)
 one year ago

ludwig457 Group TitleBest ResponseYou've already chosen the best response.0
812.65m^3/day
 one year ago
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