A game show has 4 doors, of which the contestant must choose two. Behind two are cars, behind the other two are consolation. Find the probability the contestant wins exactly one car, no cars, and at least one car. I really need to know how the number of ways P(exactly one car picked)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

A game show has 4 doors, of which the contestant must choose two. Behind two are cars, behind the other two are consolation. Find the probability the contestant wins exactly one car, no cars, and at least one car. I really need to know how the number of ways P(exactly one car picked)

Probability
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

I'd say when choosing the first door the probability to get a car is 50% (P=0.5). Then we have 3 doors left, so the probability to pick one with no car is 2/3 (P=2/3).. multiply these two and you have the probability of both events happening, which is 1/3.
There are 2 ways of winning exactly one car: (1) A car is picked on the first choice and no car is picked on the second choice: P(1 car) = 2/4 * 2/3 = 4/12 = 1/3 (2) No car is picked on the first choice and a car is picked on the second choice: P(1 car) = 2/4 * 2/3 = 4/12 = 1/3 Events (1) and (2) are mutually exclusive, therefore the probability of (1) or (2) occurring is the sum of their probabilities: 1/3 + 1/3 = 2/3

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question