1. Australopithecus

im still confused.. /;

3. zordoloom

Do you still need help??

yess

5. zordoloom

|dw:1354653752481:dw|

you are amazing, thank you so much! you made it clear too!

7. zordoloom

Yep

can you help me with one more?

9. zordoloom

Sure

What are the real or imaginary solutions of the polynomial equation? 27x3 + 125 = 0

11. zordoloom

27x^3+125=0 is the equation?

yupp

13. zordoloom

Do you also want the work?

yes please, that would actually help! i understand it better

15. zordoloom

okay.

16. zordoloom

27x^3+125=0.... so factor the left side (3x+5)(9x^2-15x+25)=0 Now split each side (3x+5)=0 (9x^2-15x+25)=0 And solve each one separably. For the first one: (3x+5)=0 ... subtract 5 and then divide by 3 You get x=-5/3 Now solve the other part using the quadratic equation.

17. zordoloom

Do you know how to use the quadratic formula? and do you follow so far?

yes!

and the other answer the same thing but its a minus sign between them am i right?

22. zordoloom

I'll just show you what I got.

23. zordoloom

|dw:1354655014389:dw|

ohhh i was completely off. ohk so thats the answer?

25. zordoloom

Yes